PH is equal to -log[ hydrogen ion]. You always have to use the concentration of the hydrogen ions. The concentration has to be in Molarity (moles per liter). If your concentration was actually 10 moles per liter, your PH would be -1. If it was 8 moles per liter, it would have a PH of -.903. The PH can actually go below 0 if you are using a strong acid in a very high concentration, but that would be dangerous.
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
The hydroxide ion concentration in a 4.0 x 10^-4 M solution of Ca(OH)2 can be calculated by first finding the molarity of OH- ions from Ca(OH)2, which is twice the molarity of the overall solution. Therefore, the [OH-] is 8.0 x 10^-4 M.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
The hydroxide ion concentration in a 4.0 x 10^-4 M solution of Ca(OH)2 can be calculated by first finding the molarity of OH- ions from Ca(OH)2, which is twice the molarity of the overall solution. Therefore, the [OH-] is 8.0 x 10^-4 M.
To calculate the molarity of a solution, you would need to divide the number of moles of solute (in this case, 10 mol of NaCl) by the volume of solution in liters (in this case, 200 L). Molarity = moles of solute / liters of solution So, Molarity = 10 mol / 200 L = 0.05 M.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
Molarity is moles per litre. So you have to convert volume to a litre. i.e. 0.5x2 is a litre. so you have to do the same to moles. 5x2 is 10 moles. as this is per litre, it is a 10 molar solution.
The molarity is 0,1 M.
So molarity means moles per litre. but you don't have a litre. if you did you'd have 1000/200 times the moles that you have. 2 moles / 200 x 1000 is 10 moles. As it is per litre, it is 2 molar.
The first step is to calculate the number of moles of the compound using the formula: moles = mass / molar mass. In this case, moles = 10 g / 100 g/mol = 0.1 moles. The molarity is then calculated by dividing the number of moles by the volume of solution in liters, so the molarity is 0.1 moles / 1 L = 0.1 M.
Molarity of hydrogen solution equals 2.3 X 10^-4 -log(2.3 X 10^-4) = 3.6 pH
10 to the 4th power is 10,000