pH = pKa + log([A-]/[HA])
pH = pKa+log([conjugate base]/[undissociated acid])
The actual meaning of pKa: the negative log of the dissociation constant, which is a measure of strength of an acid/base
when pKa = pH, there is equal concentration of acid and its conjugate base. pKa helps to understand the nature of acid and base like pH:
pKa 2 but 7 but < 10 -- weak base pKa >10 --strong base
The pOH is 6,4.
The pOH is 6,4.
10.7(pH) - 14 = 3.3 (pOH)
1.8
To find the pH from the pOH, you use the formula pH + pOH = 14. Therefore, if the pOH is 4.8, then the pH would be 9.2 (14 - 4.8 = 9.2).
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
pH + pOH =14
The pOH is 6,4.
The pOH is 6,4.
10.7(pH) - 14 = 3.3 (pOH)
1.8
It will have a pOH of 12. Because pH+pOH=14
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
pH + pOH =14
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
To find the pH from the pOH, you use the formula pH + pOH = 14. Therefore, if the pOH is 4.8, then the pH would be 9.2 (14 - 4.8 = 9.2).
pOH = 14 - pH 5 = 14 - pH 9 = pH