1 mole of any substance has 6.022 x 1023 atoms. Therefore, two moles would have
2 x 6.022 x 1023 atoms.
To find the number of moles, we need to divide the given mass of cobalt (382g) by its molar mass, which is approximately 58.93 g/mol. Therefore, 382g of cobalt contains approximately 6.48 moles of atoms.
To find the number of moles of nickel atoms in 125 g of nickel, divide the given mass by the molar mass of nickel. The molar mass of nickel is approximately 58.69 g/mol. Therefore, 125 g Ni / 58.69 g/mol = ~2.13 moles of Ni atoms.
There are 2.26 x 10^24 silver atoms in 3.75 moles of silver. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mole) by the number of moles.
There are 3.22 x 10^23 atoms in 0.534 moles of nickel (Ni). This is calculated by using Avogadro's number (6.022 x 10^23 atoms/mol) multiplied by the number of moles.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
First you have to find out the number of moles of Nickel in 0.63g. Do this by dividing 0.63 by the molecular weight of Nickel; 58.69g. 0.63/58.69= 0.01 mol (2 d.p.) In one mole there are 6.02x1023 atoms. Therefore in 0.01 moles of Nickel there will be: 0.01 x 6.02x1023 = 9.15x1015 atoms.
This number is 12,044 280 171 4.10e23.
To find the number of moles, we need to divide the given mass of cobalt (382g) by its molar mass, which is approximately 58.93 g/mol. Therefore, 382g of cobalt contains approximately 6.48 moles of atoms.
To find the number of moles of nickel atoms in 125 g of nickel, divide the given mass by the molar mass of nickel. The molar mass of nickel is approximately 58.69 g/mol. Therefore, 125 g Ni / 58.69 g/mol = ~2.13 moles of Ni atoms.
There are 2.26 x 10^24 silver atoms in 3.75 moles of silver. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mole) by the number of moles.
5,26 moles of oxygen contain 31,676.10e23 atoms.
Two moles of neon contain 12,044281714.10e23 atoms.
There are 3.22 x 10^23 atoms in 0.534 moles of nickel (Ni). This is calculated by using Avogadro's number (6.022 x 10^23 atoms/mol) multiplied by the number of moles.
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
Avogadro's number times 5.6 (or about 33.6 times ten to the 23rd power.
To determine the number of atoms in 97.6g of platinum, you first need to calculate the number of moles of platinum using its molar mass (195.08 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of platinum to atoms. This calculation will give you the total number of atoms in 97.6g of platinum.