PV = nRTV = nRT/P = (2moles)(0.0821 Latm/Kmol)(300K)/1.3 atm
V = 37.9 liters = 38 liters (2 significant figures)
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
At room temperature and pressure, 1 mole of ideal gas occupies 22.4 liters. Therefore, 8.00 moles of oxygen will occupy 8.00 x 22.4 = 179.2 liters.
The amount of oxygen is 0,067 moles.
The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, the volume of 2 moles of oxygen gas at STP would be 2 moles * 22.4 L/mol = 44.8 L.
38 L
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
38 L
38 L
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
At room temperature and pressure, 1 mole of ideal gas occupies 22.4 liters. Therefore, 8.00 moles of oxygen will occupy 8.00 x 22.4 = 179.2 liters.
The amount of oxygen is 0,067 moles.
Yes, volume is directly related to the number of moles of a substance present. This relationship is defined by the ideal gas law, which states that as the number of moles of a gas increases, the volume occupied by the gas also increases proportionally, assuming constant temperature and pressure.
The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, the volume of 2 moles of oxygen gas at STP would be 2 moles * 22.4 L/mol = 44.8 L.
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
The volume occupied by 2.12 moles of nitrous oxide is 9.35. A mole is described in chemistry as an amount of pure substance containing the same number of chemical units as there are atoms.
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
To determine the number of moles of nitrogen and oxygen in a given volume like a cubic foot, you would first need to know the pressure and temperature of the gas. Then you can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. So without knowing the pressure and temperature, it is not possible to determine the number of moles of nitrogen and oxygen in a cubic foot.