0
What else can I help you with?
What is the number of ammonium ions needed to form a compound with one phosphate ion?
Two ammonium ions are needed to form a compound with one phosphate ion. Ammonium has a positive charge of +1, while phosphate has a negative charge of -3. Therefore, two +1 charges from the two ammonium ions will balance with the -3 charge from the phosphate ion.
How can you prepare 0.1N ferrous ammonium sulphate?
To prepare 0.1N ferrous ammonium sulfate solution, dissolve the appropriate weight of ferrous ammonium sulfate crystals in a known volume of water, followed by dilution to the desired volume. The molecular weight of ferrous ammonium sulfate is needed to calculate the amount required to make the solution. Always wear appropriate personal protective equipment and handle chemicals in a well-ventilated area.
How do you prepare 0.05M Phosphate buffer of pH 6.8?
To prepare a 0.05M phosphate buffer of pH 6.8, you would need to mix a specific ratio of monosodium phosphate and disodium phosphate in a certain volume of water. The exact amounts can be calculated using the Henderson-Hasselbalch equation or by using online calculators. Adjust the pH using small amounts of acid or base as needed.
What acid is needed to produce ammonium nitrate?
Nitric acid is required to produce ammonium nitrate. Ammonium nitrate is formed by reacting nitric acid with ammonia.
HOW TO PREPARE 13.5N AMMONIUM HYDROXIDE SOLUTION?
To prepare a 13.5N ammonium hydroxide solution, you would need to dilute concentrated ammonium hydroxide solution (typically 28-30% concentration) with water in the proper ratio to achieve the desired concentration. Calculate the volume of concentrated ammonium hydroxide and water needed based on the desired final volume of the solution and mixing the two components slowly to avoid splashing. Ensure to wear appropriate personal protective equipment and work in a well-ventilated area when handling these chemicals.
What is the number of ammonium ions needed to form a compound with one phosphate ion?
Two ammonium ions are needed to form a compound with one phosphate ion. Ammonium has a positive charge of +1, while phosphate has a negative charge of -3. Therefore, two +1 charges from the two ammonium ions will balance with the -3 charge from the phosphate ion.
How can you prepare 0.1N ferrous ammonium sulphate?
To prepare 0.1N ferrous ammonium sulfate solution, dissolve the appropriate weight of ferrous ammonium sulfate crystals in a known volume of water, followed by dilution to the desired volume. The molecular weight of ferrous ammonium sulfate is needed to calculate the amount required to make the solution. Always wear appropriate personal protective equipment and handle chemicals in a well-ventilated area.
How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?
To make a 0.25 M solution of ammonium sulfate from a stock solution of 6 M, you would need to dilute the stock solution. The dilution equation is C1V1 = C2V2 where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the final solution. You would need to set up this equation to calculate the volume of the stock solution needed and then convert that volume to grams using the molar mass of ammonium sulfate.
How do you prepare 0.05M Phosphate buffer of pH 6.8?
To prepare a 0.05M phosphate buffer of pH 6.8, you would need to mix a specific ratio of monosodium phosphate and disodium phosphate in a certain volume of water. The exact amounts can be calculated using the Henderson-Hasselbalch equation or by using online calculators. Adjust the pH using small amounts of acid or base as needed.
How many grams of sulfuric acid are needed to react with 8 mol of ammonium hydroxide?
The balanced chemical equation for the reaction is 1 mol of sulfuric acid reacts with 2 mol of ammonium hydroxide. Therefore, for 8 mol of ammonium hydroxide, 4 mol of sulfuric acid are needed. To calculate the grams of sulfuric acid needed, you would multiply the number of moles by the molar mass of sulfuric acid.
How many potassium ions are needed to bond with phosphate ions?
Two potassium ions are needed to bond with one phosphate ion. Potassium has a +1 charge while phosphate has a -3 charge, so it takes two potassium ions (each with a +1 charge) to balance the charge of one phosphate ion.
What acid is needed to produce ammonium nitrate?
Nitric acid is required to produce ammonium nitrate. Ammonium nitrate is formed by reacting nitric acid with ammonia.
HOW TO PREPARE 13.5N AMMONIUM HYDROXIDE SOLUTION?
To prepare a 13.5N ammonium hydroxide solution, you would need to dilute concentrated ammonium hydroxide solution (typically 28-30% concentration) with water in the proper ratio to achieve the desired concentration. Calculate the volume of concentrated ammonium hydroxide and water needed based on the desired final volume of the solution and mixing the two components slowly to avoid splashing. Ensure to wear appropriate personal protective equipment and work in a well-ventilated area when handling these chemicals.
How many moles of silver nitrate would be required to react with 2.00 moles of sodium phosphate?
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
If the element sodium and phosphate form a compound how many of each element is needed for electroneutrality?
1 sodium, 1 phosphate
What mass of ammonium chlorate is needed to decompose to give off 200 liters of oxygen?
The molar volume of gas at STP is 22.4 L/mol. So, 200 L of oxygen is equivalent to 200/22.4 = 8.93 moles. The balanced chemical equation for the decomposition of ammonium chlorate is 2NH4ClO3 -> 2N2 + Cl2 + 3O2. Therefore, to produce 3 moles of oxygen, we need 2 moles of ammonium chlorate. 8.93 moles of oxygen would require 2/3 * 8.93 = 5.95 moles of ammonium chlorate. The molar mass of NH4ClO3 is 101.5 g/mol, so the mass of ammonium chlorate needed would be 5.95 * 101.5 = 604.5 grams.
What are the reactants of ammonium sulphate?
The reactants needed to produce ammonium sulfate are ammonia (NH3) and sulfuric acid (H2SO4). When these two substances react, they form ammonium sulfate (NH4)2SO4 and water (H2O) as a byproduct.
