The decay of 212Po84 goes like that:
212Po84 ----- 4a2 + 208Pb82
The lead isotope that forms, 208, is stable.
The daughter product that remains after the alpha decay of polonium-212 is lead-208. During alpha decay, polonium-212 loses an alpha particle, consisting of two protons and two neutrons, resulting in the transformation to lead-208.
Polonium-218 undergoes alpha decay to form lead-214, which then undergoes beta decay to form bismuth-214.
Polonium itself is not explosive. It is a radioactive element that can spontaneously decay, emitting alpha particles. However, polonium can be used to trigger a fission reaction in a nuclear bomb as part of a beryllium-polonium initiator.
Polonium 210-----------alpha particles-----------Lead 206 Polonium 209-----------alpha particles-----------Lead 205 Polonium 208-----------alpha particles-----------Lead 204 Polonium 214-----------alpha particles-----------Lead 210 Polonium 218-----------alpha particles-----------Lead 214 (99,98 %) Polonium 218-----------beta particles------------Astatin 218 (o,o2 %) For other isotopes see the list at: http://en.wikipedia.org/wiki/Polonium#Isotopes
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
The daughter product that remains after the alpha decay of polonium-212 is lead-208. During alpha decay, polonium-212 loses an alpha particle, consisting of two protons and two neutrons, resulting in the transformation to lead-208.
Polonium-218 undergoes alpha decay to form lead-214, which then undergoes beta decay to form bismuth-214.
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
Alpha decay is involved when polonium-214 decays into lead-210. In alpha decay, an alpha particle (2 protons and 2 neutrons) is emitted from the nucleus, reducing the atomic number by 2 and the mass number by 4.
All isotopes of polonium can undergo alpha decay, a small number of isotopes can also undergo beta decay, K capture decay, or gamma decay.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
The reaction is:Po-210------------alpha particle------------------Pb-206
bismuth 210 decays by beta decay to polonium 210 that decays by alpha decay to lead 206
Lead-208 is formed by alpha decay (emission of alpha particles) from polonium-212.
Polonium-210 lose an alpha particle and become lead-206.
Polonium-210 is an alpha emitter with a half-life of about 138 days. Its decay rate, or how fast it emits alpha particles, is a constant process determined by its decay constant, which is approximately 5.3 x 10^−9 per second.
Polonium 212 has 84 protons and 128 neutrons. An alpha particle is 2 protons and 2 neutrons, so the daughter nucleus will have 82 protons and 126 neutrons, making it lead 208.