24/16 = 1.5 and 18 x 1.5 = 27g
To calculate the moles of each element, you need to divide each mass by the molar mass. The molar mass of carbon is 12g/mol and oxygen is 16g/mol. 12g of carbon divided by 12g/mol gives 1 mole of carbon. 32g of oxygen divided by 16g/mol gives 2 moles of oxygen.
One mole of oxygen has a mass of 16 grams and contains 6.022 x 10^23 oxygen atoms. Therefore, 16 grams of oxygen will also contain 6.022 x 10^23 oxygen atoms.
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.
The concentration of the solution is calculated by dividing the mass of solute (urea) by the total mass of the solution and then multiplying by 100%. In this case, the concentration of the solution containing 16g of urea in 120g of solution would be 16g / 120g * 100% = 13.3%.
To find the mass of oxygen containing the same number of molecules as 42g of nitrogen, we need to compare their molar masses. The molar mass of nitrogen is 28 g/mol and oxygen is 32 g/mol. Since the same number of molecules of each substance have the same number of atoms, we can calculate the mass of oxygen by setting up a proportion: (42g N) / (28 g/mol N) = (x g O) / (32 g/mol O) Solving for x, the mass of oxygen containing the same number of molecules as 42g of nitrogen is 56g.
To calculate the moles of each element, you need to divide each mass by the molar mass. The molar mass of carbon is 12g/mol and oxygen is 16g/mol. 12g of carbon divided by 12g/mol gives 1 mole of carbon. 32g of oxygen divided by 16g/mol gives 2 moles of oxygen.
To calculate the moles of carbon dioxide, we first need to determine the number of moles of oxygen in 16g. Using oxygen's molar mass of 16 g/mol, we find that there is 1 mole of oxygen in 16g. Since one mole of oxygen reacts with one mole of carbon dioxide in the balanced equation, there will also be 1 mole of carbon dioxide formed.
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The mass of 2.000 mol of oxygen atoms is 32.00 grams.
The atomic mass of hydrogen is approximately 1 atomic mass unit, the atomic mass of nitrogen is approximately 14 atomic mass units, and the atomic mass of oxygen is approximately 16 atomic mass units.
To find the amount of oxygen used, we need to consider the difference in mass between sodium and sodium oxide. The mass increase is 16g (62g - 46g) which corresponds to the amount of oxygen used from the air. Therefore, 16g of oxygen from the air were used.
15.994 grams/mol, but it can rounded to 15.99 or 16.0 g/mol.
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
The molar mass of water(H2O)=18((1*2)+16)The no. of moles(n) of water in 18 g of water=mass/molar mass=18 g/ 18 g mol-1 =1 molThe no. of molecules of water in 18 of water=n*Avogadro no. =1 mol*6.022*1023 mol-1 =6.022*1023The no. of atoms of oxygen in one mole of water=1 molThe no. of atoms of oxygen in 6.022*1023mol of water= 6.022*1023
One mole of oxygen has a mass of 16 grams and contains 6.022 x 10^23 oxygen atoms. Therefore, 16 grams of oxygen will also contain 6.022 x 10^23 oxygen atoms.
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.
To find the number of moles in 16g of NaCl, we first need to calculate the molar mass of NaCl, which is approximately 58.44 g/mol. Then, we can use the formula: moles = mass / molar mass moles = 16g / 58.44 g/mol moles ≈ 0.27 mol