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What volume will 2.50 mole of hydrogen occupy at -20 c and 1.5 ATM?
Wiki User
∙ 7y ago
If you want more than just the answer, this is how you determine the volume.
PV = nRT
P = 1.5 atm; V = ?; n= moles H2=2.5; R=gas constant = 0.0821 Latm/Kmol; T = 253ºK
V = nRT/P = (2.5)(0.0821)(253)/1.5
V = 34.6 L = 35 L (to 2 significant figures)
Wiki User
∙ 7y ago
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How many liters of water can be produced if 250 moles of O2 are reacted with excess hydrogen?
Balanced equation first. 2H2 + O2 -> 2H2O 250 moles O2 (2 mole H2O/1 mole O2) = 500 mole H2O produced now, since I am forgetful, I will use density formula at 25 C Density = grams/milliliters 500 moles H2O (18.016 grams/1 mole H2O) = 9008 grams H2O 0.9982 g/ml = 9008 grams/milliliters 9024.24 milliliters H2O this is...... 9.02 liters of water produced in this reaction.
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What weighs about 250 milliliters?
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In chemestry what does a 'mole' describe?
a mole is a way to express how many particles there are. for example 1 mole of sand consist of 602 250 000 000 000 000 000 000 or 6.0225 × 1023 grains of sand. that's a lot, but if you're talking about atoms that is not so extremely much. for example 1 mole of table salt NaCl is only 58,44grams of salt.why use mole and not grams?I asked myself that same question, but some atoms are heavier then others and you will need more grams of it to have 1 mole, and so you can end up with very complex mathematics while you can just use moles.an other example2H² + O² --> 2H²Othis means that 2moles of hydrogen gas will react with 1 mole of oxygen gas to form 2 moles of water. this is very logical ^^ (for some people).but in grams you need 4 grams of hydrogen 32 grams of oxygen and you will end up with 36grams of water.okay it might sound more logical but look closely and you will see that oxygen gas is much heavier than hydrogen.
How many atoms are there in 250 mol Si?
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What is the number of moles of solute in 250 mL of a 0.4M solutionon centration?
1 mole in 250 ml and 4 moles in 1 liter or 1000 mls
What volume is necessary for hydrogen and oxygen to combine in a 250 ml flask?
To determine the volume necessary for hydrogen and oxygen to combine, we need to consider the stoichiometry of the reaction. Hydrogen combines with oxygen in a 2:1 ratio to form water. Therefore, twice the volume of hydrogen is required compared to oxygen. For a 250 ml flask, the volume of hydrogen required would be 166.7 ml, and the volume of oxygen required would be 83.3 ml.
How much space will a 2.5 m high cylindrical tank occupy if its diameter is 40 cm?
Volume = pi*r2*h = pi*202*250 cm3 = 314,159.3 cm3 = 314.16 litres.
What is the volume of 250 M KCl solution if it contains 2.0 mole of KCl?
250 M means contains 250 moles per liter, which is probably impossible 1) . However, taking the question as stated, the answer is (2.0 mole)/(250 moles/liter) = 0.0080 liter or 8.0 milliliters, to the justified number of significant digits.1) Commented: It is impossible!The solution in this question is really impossible in every way:The highest solubility of KCl in boiling water that is: 567 g/L (100 °C), the molar mass being 74.551 g/mol, this is 7.6 mol/L ( = 7.6 M)Even one Litre pure (molten) KCl can not contain 250 moles! The density if pure KCl is (less than) 1.984 g/cm3 , being equal to 0.027 mol/mL =27 mol/L with NO solvent added. ( = 27 M)
How many liters of water can be produced if 250 moles of O2 are reacted with excess hydrogen?
Balanced equation first. 2H2 + O2 -> 2H2O 250 moles O2 (2 mole H2O/1 mole O2) = 500 mole H2O produced now, since I am forgetful, I will use density formula at 25 C Density = grams/milliliters 500 moles H2O (18.016 grams/1 mole H2O) = 9008 grams H2O 0.9982 g/ml = 9008 grams/milliliters 9024.24 milliliters H2O this is...... 9.02 liters of water produced in this reaction.
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