low pressure and high temperature
The balanced equation is H2+ Cl2 --> 2HCl That is with a lowercase L, not an i.
Double of 11.4 L H2, so 22.8 L HCl (at the same p and T) because 1 mol H2 is made out of 2 mol HCl according to:2HCl + 2Ca --> H2 + CaCl2
Hydrogen is a gas. H2 is the description of its molecular structure (2 hydrogen atoms bound together).
Mg + H2SO4 -> MgSO4 + H2 Hydrogen gas.
Balanced equation first. Mg + 2HCl >> MgCl2 + H2 ( use PV = nRT to find moles H2 ) ( C to K ) (1atm)(6.82L) =n(0.08206Latm/molK)(308.15K) = 0.2697 moles H2 ( drive back against HCL to find those moles ) 0.2697 moles H2 (2moles HCl/1mole H2) = 0.5394 moles HCl ( conditions remain the same, so use PV = nRT to find volume HCl ) (1atm)(Vol) = (0.5394 moles HCl)(0.08206Latm/molK)(308.15K) = 13.6 Liters HCl gas required ( may be faster way, but it is many years since I have done any chemistry )
When 1.24 L of H2 gas reacts with O2 at STP, the mole ratio between H2 and H2O is 2:2. This means that for every 1 mole of H2 gas reacting, 1 mole of water is formed. Using the ideal gas law, you can calculate the number of moles of H2 gas reacting, and then use the mole ratio to determine the number of moles of water formed. Finally, you can convert moles of water to grams using the molar mass of water.
Its H2
The product of H2 is hydrogen gas (H2) composed of diatomic molecules.
It becomes the diatomic gas H2. Hydrogen gas.
The balanced equation is H2+ Cl2 --> 2HCl That is with a lowercase L, not an i.
Double of 11.4 L H2, so 22.8 L HCl (at the same p and T) because 1 mol H2 is made out of 2 mol HCl according to:2HCl + 2Ca --> H2 + CaCl2
To find the number of moles of H2 gas in 1420 mL, you need to use the ideal gas law. Given that the molar volume of gas at STP is approximately 22.4 L, you can convert 1420 mL to liters (1420 mL = 1.42 L) and then calculate the number of moles using the formula n = V/22.4, where n is the number of moles and V is the volume in liters.
At a constant temperature and pressure a mole of any gas has the same volume. So all you need to know to answer this question is that there are two atoms of hydrogen in a molecule of hydrogen gas and three atoms of hydrogen in a molecule of ammonia gas. 13.7 L * 2/3 = 9.13 L. You can check this by plugging the values into the ideal gas equation, pV = nRT (look on Wikipedia for "Ideal gas law")
Hydrogen is a gas. H2 is the description of its molecular structure (2 hydrogen atoms bound together).
The balanced equation for the reaction between hydrogen gas (H2) and iodine gas (I2) to form hydrogen iodide gas (HI) is: H2 + I2 → 2HI
NH3, as in Ammonia, like all real gases, are not ideal. Ideal gases follow the ideal gas laws, but ammonia does not adhere to a few of them. First of all, the volume of its molecules in a container is not negliggible. Next, NH3 molecules have intermolecular hydrogen bonding, which is a strong intermolecular bond. Thus, the forces of attaction between molecules is not neglible. All real gases have a certain degree of an ideal gas, but no real gas is actually ideal, with H2 being the closest to ideal.
First find moles hydrogen gas. 20 grams H2 (1 mole H2/2.016 grams) = 9.921 moles H2 Now, the ideal gas equation. PV = nRT (1 atm)(volume L) = (9.921 moles H2)(0.08206 L*atm/mol*K)(298.15 K) Volume of hydrogen gas = 243 Liters ----------------------------------------------------