HI and I-
H2O AND OH-
HOCl and OCI-
The conjugate acid of NaOH will be water. OH- has the ability to act as an acid or a base.
NaOH, or lye. They form NaCl and H2O, or salt and water.
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
No, NaOH and NaCl do not form a buffer system. A buffer system consists of a weak acid and its conjugate base, or a weak base and its conjugate acid, to help maintain a stable pH. NaOH is a strong base and NaCl is a salt, so they do not act as a buffer system together.
No, NaF and NaOH do not form a buffer solution together as a buffer solution requires a weak acid and its conjugate base, or a weak base and its conjugate acid. NaF is the salt of a weak acid (hydrofluoric acid) and a strong base (NaOH), so it does not act as a buffer. NaOH is a strong base and cannot act as a buffer solution by itself.
The conjugate acid of NaOH will be water. OH- has the ability to act as an acid or a base.
NaOH, or lye. They form NaCl and H2O, or salt and water.
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
No, NaOH and NaCl do not form a buffer system. A buffer system consists of a weak acid and its conjugate base, or a weak base and its conjugate acid, to help maintain a stable pH. NaOH is a strong base and NaCl is a salt, so they do not act as a buffer system together.
No, NaF and NaOH do not form a buffer solution together as a buffer solution requires a weak acid and its conjugate base, or a weak base and its conjugate acid. NaF is the salt of a weak acid (hydrofluoric acid) and a strong base (NaOH), so it does not act as a buffer. NaOH is a strong base and cannot act as a buffer solution by itself.
No, a buffer solution requires a significant amount of a weak acid and its conjugate base, or a weak base and its conjugate acid, in roughly equal amounts. The reaction between HCl and NaOH results in the formation of water and salt, not a buffer solution.
When NaOH is added to a buffer, the change in pH can be calculated using the Henderson-Hasselbalch equation. This equation is pH pKa log(A-/HA), where pKa is the acid dissociation constant of the weak acid in the buffer, A- is the concentration of the conjugate base, and HA is the concentration of the weak acid. By plugging in the initial concentrations of the weak acid and its conjugate base, as well as the amount of NaOH added, you can calculate the change in pH.
Sodium is as the cation Na+; and the anion is (OH)-.
The reaction between ethyl 4-aminobenzoate and NaOH would involve the amine group of the 4-aminobenzoate being deprotonated by the strong base NaOH. This would result in the formation of the conjugate base of the amine group and water as a byproduct. The equation for this reaction can be represented as follows: Ethyl 4-aminobenzoate + NaOH → Ethyl 4-aminobenzoate-Na+ + H2O
NaOH - Sodium ion (Na+) has a +1 charge, while hydroxide ion (OH-) has a -1 charge. NaOH - Sodium ion (Na+) has a +1 charge, while hydroxide ion (OH-) has a -1 charge.
Quantity matters. If there is a lot of buffer (in terms of moles) and relatively little NaOH then the buffer will prevent any change in pH. If there is relatively more NaOH than buffer, then of course the pH will rise.
NaOH was added to convert the acidic component into its conjugate base, making it water-soluble and enabling its extraction into the aqueous phase. HCl was then added to neutralize the basic component and convert it back into its neutral form, making it extractable into the organic phase. Equation: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)