the first orbital to be filled is 1s because in this orbital the negatively charged electron is closer to the positively charged nucleus than in any other orbital
Quoted directly from my Chenistry Text Book ( World of Chemisty Zumdahl/Zumdahl/DeCoste , p377 McDougal Littell 2007)
The 1S orbital is the closest orbital to the nucleus and therefore it has the lowest energy level.
the first one
Two electrons can fit into the first orbital shell of any atom.
In an atom, electrons are in "shells", the first shell is around the center of the atom and holds a maximum of 2 electrons. Each subsequent shell out, will hold a maximum of 8 electrons. there is no maximum number of shells.
Yes a single orbital in the 3d level can hold 2 electrons.
s orbitals are spherical, so there cannot be any angle 'between' an s orbital and a p orbital. However, each lobe of a p orbital is perpendicular (90 degrees in all directions) to the surface of an s orbital.
There's two ways to answer this question. First electron configurations with half-filled sublevels are more stable then electron configurations that don't have half-filled sublevels. Since Selenium is one elctron away from achieving a more stable half-filled sublevel configuration it more readily gives up it's outermost electron, so less energy is requires to remove the outermost electron. Arsenic already has the stable configuration of half-filled sublevel so it wouldn't give up it's electron as readily, so more energy is required to remove it. Another way to look at it is that Selenium's outermost electron is in a p orbital that already has an electron so there is electron electron repulsion present in that orbital so it's attraction to the nucleus is less which is why less energy is required to remove it so the ionization energy is less. Arsenic has it's outermost electron unpaired in the p orbital so there is no electron electron repulsion present in that orbital so more energy is required to remove it then for Selenium's outer most electron. Hope this helps!
A filled orbital has either 2 electrons (if it is the first shell of an atom) or 8 electrons. This is the highest number of electrons these shell can hold Every orbital tends to complete itself to form a stable element. A filled orbital could be any orbital, either 1st, 2nd, second last or last shell of the atom. An unfilled orbital always has atleast one less electron than the shell can hold. It is always the last shell of an atom and always makes the atom unstable as atom tends to acquire inertness by trying to get this unfilled oribital filled.
Any orbital is complete when it contains 2 electrons.
Two electrons can fit into the first orbital shell of any atom.
There is technically a 9i orbital, but no atom in the ground state has any electrons in this orbital (in fact, no known element has any electrons in even the 8s orbital, and there are quite a few energy levels between that and 9i). In an excited state ... sure, it could happen.
he2 is a fatty. He atom is a inert gas. so it can not react with any other atom or molecules to form any compounds.so He2 can't exist. ANOTHER ANSWER: Helium atom has only one shell i-e K-shell which can accommodate a maximum of two electrons which it already has. therefore Helium atom does not need any more electrons to become stable as it is already stable by duplet rule. Thus helium atom does not combine with another helium atom and hence exists as He and not He2.
The lowest energy level that has F orbitals is the fourth energy level. The Atomic orbital of any atom only contains 2 electrons.
When fluorine (F) takes an electron from sodium (or from any element in an ionic bonding scenario), the 2p6 sub-orbital is filled, which allows fluorine to achieve the electron configuration of nearby neon (Ne).
6 electrons can ocupy the 2p, 3p, 4p, and so on. each p subshell has 3 orbitals, and each orbital can hold up to 2 electrons, so each p subshell can hold up to 6 electrons total.
Assuming the electron is in the lowest states and the atom is neutrally charged, it will fill an orbital before extending the next one. 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p H and He fill 1s as it holds two electrons. Li and Be fill 2s as it holds two electrons. B, C, N, O, F, and Ne will fill the 2p orbital as it holds 6 electrons (2p1, 2p2, and 2p3 orbitals). However, nitrogen will have one electron in each 2p1, 2p2, and 2p3 orbitals as an electron will not go two to an orbital until each orbital is filled. Neon completes the 2p orbital and is very stable (considered an inert gas--electrons are neither attracted nor want to leave the completed 2p orbital). Fluorine is the most electronegative element, as it wants to rip any electron it can to fill its 2p orbital. All noble gasses (right most on the periodic table) will complete a p-orbital. Periods 3-12 will fill a d-orbital. Lanthanoids and actinoids will fill the f-orbitals. So, for instance, Calcium (Ca) has an atomic number 20. You look up Ca on the periodic table. As it comes after He, it will have a 1p orbital filled. As it comes after Be, it will have a 2s orbital filled. As it comes after Ne, it will have a 2p orbital filled. And Ca will have a 3s orbital filled. Therefore, you note that Ca has electrons in the following orbitals: 1s, 2s, 2p, 3s. Another example is Fluorine (F), which would be: 1s, 2s, 2p1(2), 2p2(2), 2p3(1) where the parenthetical numbers note the number of electrons in each orbital.
the pauli exclusion principle
Thier is a total of Seven orbits per atom.
A chemical stable atom is when it has the same number has electrons and protons. When the electrons and the protons are same it cannot react with any other atom till then and the atoms are called as inert atoms.