The balanced equation for the reaction between sulfuric acid (H2SO4) and potassium nitrate (KNO3) to produce nitric acid (HNO3) is: H2SO4 + 2KNO3 -> 2HNO3 + K2SO4
From the balanced equation, it can be seen that for every mole of sulfuric acid reacting, two moles of potassium nitrate are required to produce two moles of nitric acid. This is due to the stoichiometry of the reaction, where the coefficients in the balanced equation represent the mole ratios of the reactants and products.
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
To calculate the moles of H2SO4 in a titration, you can use the formula: moles Molarity x Volume. First, determine the molarity of the H2SO4 solution. Then, measure the volume of the solution used in the titration. Multiply the molarity by the volume to find the moles of H2SO4.
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
To find the number of moles of H2SO4 in 100 mL of 12M H2SO4 solution, you first need to convert the volume to liters, which is 0.1 L. Then, you multiply the volume in liters by the molarity to get the moles of H2SO4. So, 0.1 L * 12 mol/L = 1.2 moles of H2SO4.
9.62 Mol H2SO4 ( 6.022 X 10^23/1mol H2SO4 ) = 5.79 X 10^24 molecules of H2SO4
To calculate the mass of a substance in grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. Therefore, the mass of 6.25 moles of H2SO4 would be 6.25 moles x 98.08 g/mol = 613 grams.
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.