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KI reacts with Cu2+ ions and then the CuI2 formed dicomposes to give insoluble CuI salt and I2. The iodine makes the solution brown.
Cu2+ + 2I− → CuI2
2 CuI2 → 2 CuI + I2
Sodium thiosulfate can be added to this mixture. It reacts with the iodine giving a white ppt in a colourless solution.
What else can I help you with?
What is the test for hydrogen iodide?
Hydrogen iodide can be tested using silver nitrate solution. When hydrogen iodide is bubbled through silver nitrate solution, a yellow precipitate of silver iodide is formed. This confirms the presence of iodide ions in the sample.
In estimation of copper and nickel why we are using volumetric for copper and gravimetric for nickel seperately?
It is simply because they could not be found together!! copper can be estimated by treating with potassium iodide and iodine will be liberated in the reaction which is titrated against sodium thiosulphate during the reaction we will add sulphuric acid to prevent the hydrolysis of copper sulphate and we follow by, adding ammonia to neutralize sulphuric as it may hinder the reation between iodide and copper!! now again we will add acetic acid to neutralize ammonia.. and the indicator is added at the last because it will get absorbed with the iodine!! now atlast we add ammonium, thiocyanate to prevent the excess of iodine getting added to copper iodide. end point is disappearance of blue color.
What happen when you add iodide to silver nitrate?
When iodide is added to silver nitrate, a chemical reaction occurs, resulting in the formation of silver iodide precipitate. This can be represented by the equation: AgNO3 + KI -> AgI(s) + KNO3. The silver iodide formed is insoluble in water and appears as a yellow precipitate.
What happen if you add the copper sulphate to sodium hydroxide?
If you add copper sulfate to sodium hydroxide, a double displacement reaction will occur. The copper sulfate will react with the sodium hydroxide to form copper hydroxide, which is a blue solid, and sodium sulfate, which is a soluble compound. This reaction is often used in qualitative analysis to test for the presence of copper ions.
What is the difference between starch solution and iodine solution?
Starch is composed of amylose and amylopectin, and is not soluble in water due to the presence of amylopectinIodine (I₂) is somewhat soluble in water, but is more soluble in iodide (I⁻) solutions, such as potassium iodide solution (KI).Aqueous iodine molecules (I₂) and iodide ions (I⁻) together will form triiodide ions (I₃⁻), which can react with amylose found in starch to produce a deep-blue colour in the solution. So all of iodide (I⁻), iodine (I₂) and amylose (or starch) are required together to produce the colour.This can be used to test for:Amylose/Starch: Add iodine dissolved in potassium iodide solution to test solution, orIodine: Add starch and potassium iodide solutions to test solution.If the substance being tested for is present, then triiodide ions (I₃⁻) can react with amylose (in starch) to produce a deep-blue colour, that is, a positive result.
Add an excess of potassium iodide to copper sulphate solution how much is excess?
The amount of excess potassium iodide depends on the stoichiometry of the reaction between potassium iodide and copper sulfate. One equivalent of potassium iodide is needed to react with one equivalent of copper sulfate. Excess potassium iodide would be any amount added beyond this stoichiometric ratio.
What is the test for hydrogen iodide?
Hydrogen iodide can be tested using silver nitrate solution. When hydrogen iodide is bubbled through silver nitrate solution, a yellow precipitate of silver iodide is formed. This confirms the presence of iodide ions in the sample.
How would you remove essentially all the iodine while leaving the water in the bag?
How to remove iodine from a solution of water? I'm assuming your talking about a iodine salt (such as sodium iodide) as elemental iodine (I2) is not that soluble in water. To remove simply add in another salt (such as copper sulfate) that will react with the iodide producing an insoluble salt (copper iodide) which can then be removed.
In estimation of copper and nickel why we are using volumetric for copper and gravimetric for nickel seperately?
It is simply because they could not be found together!! copper can be estimated by treating with potassium iodide and iodine will be liberated in the reaction which is titrated against sodium thiosulphate during the reaction we will add sulphuric acid to prevent the hydrolysis of copper sulphate and we follow by, adding ammonia to neutralize sulphuric as it may hinder the reation between iodide and copper!! now again we will add acetic acid to neutralize ammonia.. and the indicator is added at the last because it will get absorbed with the iodine!! now atlast we add ammonium, thiocyanate to prevent the excess of iodine getting added to copper iodide. end point is disappearance of blue color.
What happen when you add iodide to silver nitrate?
When iodide is added to silver nitrate, a chemical reaction occurs, resulting in the formation of silver iodide precipitate. This can be represented by the equation: AgNO3 + KI -> AgI(s) + KNO3. The silver iodide formed is insoluble in water and appears as a yellow precipitate.
What happen if you add the copper sulphate to sodium hydroxide?
If you add copper sulfate to sodium hydroxide, a double displacement reaction will occur. The copper sulfate will react with the sodium hydroxide to form copper hydroxide, which is a blue solid, and sodium sulfate, which is a soluble compound. This reaction is often used in qualitative analysis to test for the presence of copper ions.
How can distingished sodium chloride from sodium iodide?
Take a few drops of both samples and add some lead nitrate. A yellow precipitate indicates lead iodide and it gives the inference that it contains iodide ions, hence the solution of sodium iodide.
When you add lead nitrate and Potassium Iodide and filter them what is the solid?
The solid formed when adding lead nitrate and potassium iodide and filtering the mixture is lead iodide. Lead iodide is a yellow precipitate that forms by the reaction between lead nitrate and potassium iodide.
What do you get when you add copper to oxygen?
Copper(II) Oxide
What is the difference between starch solution and iodine solution?
Starch is composed of amylose and amylopectin, and is not soluble in water due to the presence of amylopectinIodine (I₂) is somewhat soluble in water, but is more soluble in iodide (I⁻) solutions, such as potassium iodide solution (KI).Aqueous iodine molecules (I₂) and iodide ions (I⁻) together will form triiodide ions (I₃⁻), which can react with amylose found in starch to produce a deep-blue colour in the solution. So all of iodide (I⁻), iodine (I₂) and amylose (or starch) are required together to produce the colour.This can be used to test for:Amylose/Starch: Add iodine dissolved in potassium iodide solution to test solution, orIodine: Add starch and potassium iodide solutions to test solution.If the substance being tested for is present, then triiodide ions (I₃⁻) can react with amylose (in starch) to produce a deep-blue colour, that is, a positive result.
What is the chemical name for CuCI2?
CuI3 would be a compound of the triiodide ion, I2 + I- --> (I3)- however i think its highly unlikely that you could ever make cuprous triiodide because you would have to mix a soluble cupric compound like CuSO4 with a soluble triiodide compound like thallium triiodide and the the triiodide would react with the cupric ions to form iodine and cuprous iodide. 4TlI3 +2CuSO4 --> 2Tl2(SO4) + 2CuI +5I2
How do you test for halide ions?
If you wish to test for the presence of halogen in an iodoform, then you must first inject the iodoform with a touch of helium. This helium will make the halogen react and change colors, making it notable in the iodoform.
