What is the bit rate of a signal in which 10 bit lasts 20 microseconds?
20/10= 2μs
2μs = 2/1000000 = 0.000002 s
bit rate = 1/(bit duration) = 1 / (0.000002) = 500,000 bps = 500 Kbps
500000bps
500
What is the baud rate of a digital signal that employs the differential Manchester scheme and has a data transfer rate of 2000 bps.
The two terms are used frequently in data communication are bit rate and the baud rate. Bit rate can be defined as the number of bits transmitted during 1s. Baud rate can be referred as to the number of the signal units per second that are required to represent those bits. A signal unit is composed of one or more bits. In discussions of the computer efficiency, the bit rate is the important; we want to know how long it takes to process each and every piece of information. In data transmission, however, we more concerned with how efficiently we can move those data from one place to another, either in pieces or blocks. The fewer signals units required, the more efficient the system and less bandwidth required to transmit more bits; so we are more concerned with baud rate. The baud rate determines the bandwidth requires sending the signal. Bit rate equals the baud rate times; number of bits represented by each signal unit. Baud rate equals the bit rate divided by number of bits represented by each signal unit. The bit rate is always greater than or in some cases equal to the baud rate. So we can say that the bit rate is the number of bits per second while Baud rate is number of signal units per second.
QAM-64 encodes 6 bits per symbol (2^6=64). Baud rate = symbol rate = bit rate / bits per symbol = 72000 bps / 6 bits per symbol = 12000
E1 support bit rate of 2.048 Mbps and contains 30 no of DSOs.
The jam signal is a signal that carries a 32-bit binary pattern sent by a data station to inform the other stations that they must not transmit.
Bit rate = 8 / (16 * 10-9) bits/second
a 1 bits/second b 500 bits per second c 500 bits per second. I assume you meant 20 msec for c.
i think its 96000BPS
32 kHz
Bit Interval: The time required to send one signal bit. Bit Rate: The number of bits that are conveyed or processed per unit of time. (Example: 100MB/sec)
The bit rate of a signal in which the time per bit is know can be easily calculated. The bit rate for a signal where a bit lasts for 0.001 seconds can be found directly by inverting the time per bit. But let's look at it this way. Your bit takes 0.001 seconds to be completed. That's 1/1000th of a second. That's a rate of 1/1000th of a second per bit, isn't it? Yes, it is. But bit rate is bits per second, and you have seconds per bit, right? Yes, you do. It turns out that 1/1000th of a second per bit is exactly equal to one bit per 1/1000th of a second. It is most important that this is clear. Your bit rate is one bit per thousandth of a second. But wait a minute. Bit rate is normally measures in "x" number of bits per one second, and the bit rate here is expressed here as one bit per 1/1000th of a second. Here's what it looks like: 1 bit________________________1/1000th seconds Looks kinda ugly, but that's what it is. Now multiply both the numerator (1 bit) and the denominator (1/1000th seconds) by 1000. That makes the denominator turn into a 1 which is what is needed to convert this mess into bits per 1 second. The numerator will be come 1000. The answer is now clear. It's 1000 bits per one second, or 1000 bits per second, or 1000 bps, or 1k bps.
Basically the baud rate can never be greater than the bit rate. Baud rate can only be equal or less than the bit rate. However, there are instances that baud rate maybe greater than the bit rate. In Return-to-zero or Manchester encoding, where there are two signaling elements, the baud rate is twice the bit rate and therefore requires more bandwidth.
What is the baud rate of a digital signal that employs the differential Manchester scheme and has a data transfer rate of 2000 bps.
Answeryes it is AnswerRb = 4000 bpsTb = 1/Rb = 250 μsKotsos
3000 Hz
Baud Rate=8000 Each signal change=4 bits (4 bits yield 16 combinations) Therefore: (4*8000)=32000bps
The two terms are used frequently in data communication are bit rate and the baud rate. Bit rate can be defined as the number of bits transmitted during 1s. Baud rate can be referred as to the number of the signal units per second that are required to represent those bits. A signal unit is composed of one or more bits. In discussions of the computer efficiency, the bit rate is the important; we want to know how long it takes to process each and every piece of information. In data transmission, however, we more concerned with how efficiently we can move those data from one place to another, either in pieces or blocks. The fewer signals units required, the more efficient the system and less bandwidth required to transmit more bits; so we are more concerned with baud rate. The baud rate determines the bandwidth requires sending the signal. Bit rate equals the baud rate times; number of bits represented by each signal unit. Baud rate equals the bit rate divided by number of bits represented by each signal unit. The bit rate is always greater than or in some cases equal to the baud rate. So we can say that the bit rate is the number of bits per second while Baud rate is number of signal units per second.