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How many network and host bits are available for class C IP address?
By default Class C subnet mask is 255.255.255.0 = 24 bits for network id and 8 bits for host id. in Binary 1111 1111. 1111 1111. 1111 1111. 0000 0000 Here all 1s are Network bits and all 0s are host bits. For this subnet mask you can have 256 hosts. And you can use 254 host and asign IP address to them. By Saurabh
What is used to specify which bits of an ipv4 address are used for the network identifier and which bits are used for the host identifier?
Subnet Mask
As network administrator what is the subnet mask that allows 510 hosts given the IP address?
N - network bitsH - host bitsIf you are following the first octet rule, this is a class B network with a subnet mask of 255.255.0.0 (N.N.H.H). We can subnet this by "borrowing" some bits from the host portion. There are 16 network bits and 16 host bits. There is a simple formula to calculate the proper subnet mask.2 to the power of what equals at least 510(2^X)? We have a total of 16 host bits to borrow from. 2^1...2^2...2^3...Etc2^9= 512 - 2 = 510 host addressesWe subtract two because the network and broadcast address are not usable addresses. As we can see we need at least 9 host bits to get 510 hosts per subnet.Take 32 and subtract it from the host bits you need. So 32-9=23. Your subnet mask now has 23 network bits instead of 16.In binary the original subnet mask would be 11111111.11111111.00000000.00000000.In binary the new subnet mask is 11111111.11111111.11111110.00000000.If you convert this into dotted decimal form you get 255.255.254.0.TLDR: 172.30.0.0 - 172.30.1.255255.255.254.0
A host with the IP address 172.32.65.13 and a default mask belongs to what network?
Since this is a class B with the default subnet mask the network would be: 172.32.0.0
How to use 172.16.0.0 to create 32 subnets?
172.16.0.0 is really a B Class address with 16 network bits and 16 host bits, i.e. Network Address 172.16.0.0 has 255.5255.0.0 as Subnet mask in Classful Addressing. To create 32 (25) subnets we will use first five bits for Network part and will leave 3 bits as Host bits in third octet. Now Addressing will be:Network Address: 172.16.0.0\21 or 172.16.0.0 Subnet Mask: 255.255.248.0First two networks will be : (1) 172.16.0.0-172.16.7.255\21, (2) 172.16.8.0-172.16.15.255\21 and last two networks will be (1) 172.16.240.0-172.16.247.255\21, (2) 172.16.248.0-172.16.255.255\21.(Note to use Zero subnet - remember to use IP SUBNET ZERO command.)
How many bits are available for class b host ip address using a default subnet mask?
The default mask class B is 255.255.0.0 and this makes 16 bits available for hosts
How many network and host bits are available for class C IP address?
By default Class C subnet mask is 255.255.255.0 = 24 bits for network id and 8 bits for host id. in Binary 1111 1111. 1111 1111. 1111 1111. 0000 0000 Here all 1s are Network bits and all 0s are host bits. For this subnet mask you can have 256 hosts. And you can use 254 host and asign IP address to them. By Saurabh
The default subnet mask for the host IPv4 address 123.232.203.145 is?
The default subnet mask for this address - a class A address - is 255.0.0.0 (same as /8).
How you subnet ip address using class b?
Same as subnetting any other class, or a classless network. From the bits originally reserved for the host (16 bits, in the case of a class B address), you "borrow" some bits, that is, you use them to specify the subnet. The remaining bits specify an individual host within a subnet.
How do you know which bits are host bit in a subnet mask?
Since a subnet mask is used to separate the network id from the host id, any 1 bits indicate the network portion and the 0 bits indicate host portion. As an example, in the subnet mask: 255.255.0.0 This indicates the first two octets are used for the network, and the last two octets (ipV4) are used for host portion of an address.
What is the default subnet mask for the IP address 176.43.52.18?
255.0.0.0 for a class A correct. but why? well, 10.10.0.0 is a class a network and all class "a" networks use a default subnet mask of 255.0.0.0. the range of class "a" networks is 1-126.
Explain what is the subnet id of host 86.212.118.145 given a subnet mask 255.0.0.0?
You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.
How many network and host bits are available in ipv4?
In IPv4, there are a total of 32 bits in an IP address. The number of network and host bits varies depending on the subnet mask used. Typically, the first part of the bits represents the network portion, while the remaining bits represent the host portion. For example, in a common subnet mask of 255.255.255.0 (or /24), there are 24 bits for the network and 8 bits for hosts.
How many subnets and hosts per subnet can you get from the network 172.16.0.0?
There are 16 bits available; it is up to you how many of those bits you reserve for the subnet, and how many for the individual hosts within each subnet.
What is used to specify which bits of an ipv4 address are used for the network identifier and which bits are used for the host identifier?
Subnet Mask
As network administrator what is the subnet mask that allows 510 hosts given the IP address?
N - network bitsH - host bitsIf you are following the first octet rule, this is a class B network with a subnet mask of 255.255.0.0 (N.N.H.H). We can subnet this by "borrowing" some bits from the host portion. There are 16 network bits and 16 host bits. There is a simple formula to calculate the proper subnet mask.2 to the power of what equals at least 510(2^X)? We have a total of 16 host bits to borrow from. 2^1...2^2...2^3...Etc2^9= 512 - 2 = 510 host addressesWe subtract two because the network and broadcast address are not usable addresses. As we can see we need at least 9 host bits to get 510 hosts per subnet.Take 32 and subtract it from the host bits you need. So 32-9=23. Your subnet mask now has 23 network bits instead of 16.In binary the original subnet mask would be 11111111.11111111.00000000.00000000.In binary the new subnet mask is 11111111.11111111.11111110.00000000.If you convert this into dotted decimal form you get 255.255.254.0.TLDR: 172.30.0.0 - 172.30.1.255255.255.254.0
How many usable host are available given a Class C IP address with the default subnet mask?
with the default subnet mask, the number of clients in a class A network is: 16,777,214
