How many bits would be needed to represent a 64 character?

Answer 1

That depends on the character code used:

• baudot - 5 bits per character - 320 bits
• FIELDATA - 6 bits per character - 384 bits
• BCDIC - 6 bits per character - 384 bits
• ASCII - 7 bits per character - 448 bits
• extended ASCII - 8 bits per character - 512 bits
• EBCDIC - 8 bits per character - 512 bits
• Univac 1100 ASCII - 9 bits per character - 576 bits
• Unicode UTF-8 - variable bits per character - depends on the characters in the text
• Unicode UTF-32 - 32 bits per character - 2048 bits
• Huffman coding - variable bits per character - depends on the characters in the text

Answer 2

It takes 8 bits to form 1 byte which equals 1 character (255 variants are possible).

True, but some languages (eg Japanese) which use Kanji characters require more than one byte.

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It depends on the encoding your using. With the ASCII encoding (which is, more or less, "standard" in most English-speaking countries, such as the United States), each character requires 1 byte.

However, another encoding, known as "Unicode", has become increasingly prominent, even in English-speaking countries. A Unicode character requires 2 bytes to store a single character. Some programming languages are even beginning to make Unicode the default Encoding, or include some features that enables Unicode throughout a single project. Currently, the "System.String" class within the .NET Framework is made up of purely Unicode characters, with no capacity to change this without implementing some kind of a 'hack'.

Answer 3

If you mean "64 different characters", you need log2(64) = 6 different bits.

Answer 4

help

Answer 5

i dont know

Answer 6

2

Answer 7

6

Answer 8

8

Answer 9

64