12.90
(Explanation): use charle's law for this one. V/T=V/T. we know the temperatures in both scenarios, and we're trying to solve for the volume in the beginning. Remember temperature in Kelvin! So, plug in what we know to get V/224.97K =29.164/508.59K. Now, cross-mulitply to solve for V. Equation now looks like this 508.59V=6561.02508. Now, divide by 508.59 on both sides to get 12.90042093. Round to 4 sig figs, 12.90 DONE!
- by the variation of the temperature- by the variation of the pressure
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
According to Charles's Law, the volume of a gas is directly proportional to its Kelvin temperature when pressure is constant. Therefore, if the Kelvin temperature triples, the gas volume will also triple, so the gas volume will be 9 liters.
Assuming the temperature remains constant, we can use Boyle's Law which states that pressure and volume are inversely proportional at constant temperature. If the volume is halved from 8.0 liters to 4.0 liters, the pressure will double from 70 kilopascals to 140 kilopascals.
It would be approx 9042 litres.
An experimental gas law is the Charles Law. The formula used is original volume/original temperature= new volume/new temperature. The law describes expansion of gases with heat.
Of course. But at STP, any gas has a standard volume of 22.4 Liters.
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
Liters is a measurement of volume. 160 Liters is the volume.
The volume increases.
Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
At standard temperature and pressure (STP), the volume occupied by 1 mole of any ideal gas is 22.4 liters. Therefore, the volume of 1.42 moles of ammonia at STP would be 1.42 * 22.4 liters = 31.808 liters.