Memory called RDRAM that conforms to the RIMM form factor.
16-bit memory
SIMM
GREGS
DRAM
Real mode uses 16 bit data path while protected mode uses 32 bit data path.
The 8088 brings in data in 8 bit chunks form the memory and must bring in two because internally it is 16 bit. The 8086 brings in the full 16 bits at one time. so it is the path to memory that differs.
The Intel 8085 microprocessor uses an 8-bit data bus and a 16-bit address bus. It can address 64 KB of memory, with each memory location capable of storing a byte. Therefore, the maximum positive number that can be represented in an 8-bit register is 255 (2^8 - 1), while in a 16-bit address space, the maximum is 65,535 (2^16 - 1) when considering the entire memory range.
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
16 bit without ECC and 18 bit with ECC Source : A+ Guide to hardware 4e
RIMM
ip address
The 16 in the description would be how much memory it has. If it says "IPad 16" then it is most likely an IPad with 16 GB of memory. A person uses memory for everything on an IPad from pictures to apps.