20
2 teaspoons is 10 ml.
There are 48 mL of acid in 320 mL of a 15% acid solution. This is calculated by multiplying the volume of the solution by the percentage of acid in the solution: 320 mL x 0.15 = 48 mL.
a ml of 36n or 18m sulphuric acid should weigh approx 1.84g. This is because conc sulphuric acid's density is 1.84g/ml
2
A 50 ml solution that is 10% acid will consist of 5 ml of acid (10% of the volume) and 45 ml of water (90% of the volume). You're not adding any water, but you want to add enough acid to make a solution that is 50% acid and 50% water. You will need to have a total of 45 ml of acid in the mixture to make it a 50/50 solution, since the amount of water is also 45 ml. You have 5 ml in there already, so you would need to add 40 ml of acid. That would make a total 90 ml solution that is 50% water (45 ml) and 50% acid (45 ml).
12.5 ml grams
it has aproximately 35 grams of acid per every 3 mL of V8
1ml of water weighs 1gram, so it would be a safe bet to say 20 grams
To calculate the amount of pure acid in the solution, you can use the formula: amount of pure acid = volume of solution * concentration of acid. In this case, it would be 860 mL * 0.19 = 163.4 mL of pure acid in the solution.
The volume of acetic acid would be 23.65 mL : 473 mL x 0.05 acetic acid/mL = 23.65 mL acetic acid
18% of 330 = 59.4 So there are 59.3ml of pure acid in 330ml of 18% acid solution.
50% citric acid powder = 50 g citric acid/100 g 4% citric acid solution = 4 g citric acid/100 ml distilled water Determining how much citric acid powder to use is based upon how much citric acid solution you wish to make. To make 100 ml of solution, you should use 8 g of powder.