150
12 g of carbon will have 6.023 x 1023 atoms of carbon
A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.
6.55 * 1024 atoms = ? moles of carbonTake the number of atoms and divide it by Avogrodos constant (6.02 * 1023). Note that if you are looking to have your units cancel, multiply the number of atoms times 1 mole and divided by atomic mass. But if you know why it is just multiplied by one, there is no reason to put it in the formula.6.55 * 1024 atoms / (6.02 * 1023) = 10.9 molescarbon
Feb. 20th to 24th
4.65Mol
1.08 x 10^25
1,400,000,000,000,000,000,000,000
2.44 times 10 to the 24th power
0.00000000000000000000000167
5,970,000,000,000,000,000,000,000 kilograms.
Ten to the 24th power, 1024, is called ten to the 24th power.
2.44 x 1024 = 2440000000000000000000000
2 to the 24th power is 16,777,216.
3.75 X 1024 molecules carbon dioxide (1 mole CO2/6.022 X 1023) = 6.23 moles carbon dioxide ==================
5.974 x 10^24 (5.974 times 10 to the 24th power)
1.292557881
The answer is 6,227 moles.