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Your exponent is missing. To convert number of ___ (electrons, protons, atoms, molecules, etc) to moles of that substance, you must divide the number of ____ by Avogadro's constant (or Avogadro's number, commonly abbreviated to N_A (_A meaning the A is a subscript). Wikipedia lists the number as 6.02214179(30) e23 (e23 is a shortform of scientific notation, where the e refers to "times ten to the power of").

The brackets at the end of the decimal are the area of uncertainty. Since Avogadro's constant is defined as the number of carbon atoms in exactly 12 grams of the carbon-12 isotope, we cannot affix a specific number - there is no way (as far as I know) of counting individual atoms, accurately measuring mass to the point where a 1 atom difference is detectable, or ensuring the sample being weighed is nothing but carbon-12.

Most chemistry classes in high school and undergraduate university/college classes will accept 6.022e23 as an acceptable approximation; add more decimals as required - if you're doing original research you should probably include the number specified in a more reliable source than wikipedia.

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14y ago
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13y ago

Avogadro's number, which is defined as the number of units in one mole, is 6.022 X 1023. Therefore, the answer to this question is (4.2 X 1024)/(6.022 x 1023) = 0.70 moles, to the justified number of significant digits (limited by "4.2").

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6y ago

0.682 mol CO2

Refer to the process below.

One mole of anything is 6.022 x 1023 anythings, including molecules.

Multiply the molecules CO2 by (1 mol CO2)/(6.022 x 1023 molecules CO2).

4.11 x 1023molecules CO2 x (1 mol CO2)/(6.022 x 1023molecules CO2) = 0.682 mol CO2 (rounded to three significant figures)

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12y ago

4.6X10^24 (1 mol Pb / 6.02X10^23 *Avagadros number*) = 7.6

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13y ago

4.32 X 10^21 atoms of vanadium (1 mole V/6.022 X 10^23)

= 0.00717 moles of vanadium

7.17 X 10^-3

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12y ago

3.4 X10^24 atoms Pb (1 mole atoms Pb/6.022 X 10^23)

= 5.6 moles of lead atoms

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11y ago

4.71 X 1021 atoms lead (1 mole Pb/6.022 X 1023)

= 0.008 moles lead

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7y ago

4,75 moles of Pb contain 932,4 g.

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12y ago

0.00782

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Q: How many moles of atoms in 4.2 times 10 to the 24th Pb atoms?
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