Your exponent is missing. To convert number of ___ (electrons, protons, atoms, molecules, etc) to moles of that substance, you must divide the number of ____ by Avogadro's constant (or Avogadro's number, commonly abbreviated to N_A (_A meaning the A is a subscript). Wikipedia lists the number as 6.02214179(30) e23 (e23 is a shortform of scientific notation, where the e refers to "times ten to the power of").
The brackets at the end of the decimal are the area of uncertainty. Since Avogadro's constant is defined as the number of carbon atoms in exactly 12 grams of the carbon-12 isotope, we cannot affix a specific number - there is no way (as far as I know) of counting individual atoms, accurately measuring mass to the point where a 1 atom difference is detectable, or ensuring the sample being weighed is nothing but carbon-12.
Most chemistry classes in high school and undergraduate university/college classes will accept 6.022e23 as an acceptable approximation; add more decimals as required - if you're doing original research you should probably include the number specified in a more reliable source than wikipedia.
Avogadro's number, which is defined as the number of units in one mole, is 6.022 X 1023. Therefore, the answer to this question is (4.2 X 1024)/(6.022 x 1023) = 0.70 moles, to the justified number of significant digits (limited by "4.2").
0.682 mol CO2
Refer to the process below.
One mole of anything is 6.022 x 1023 anythings, including molecules.
Multiply the molecules CO2 by (1 mol CO2)/(6.022 x 1023 molecules CO2).
4.11 x 1023molecules CO2 x (1 mol CO2)/(6.022 x 1023molecules CO2) = 0.682 mol CO2 (rounded to three significant figures)
4.6X10^24 (1 mol Pb / 6.02X10^23 *Avagadros number*) = 7.6
4.32 X 10^21 atoms of vanadium (1 mole V/6.022 X 10^23)
= 0.00717 moles of vanadium
7.17 X 10^-3
3.4 X10^24 atoms Pb (1 mole atoms Pb/6.022 X 10^23)
= 5.6 moles of lead atoms
4.71 X 1021 atoms lead (1 mole Pb/6.022 X 1023)
= 0.008 moles lead
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4,75 moles of Pb contain 932,4 g.
0.00782
4.65Mol
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
12 g of carbon will have 6.023 x 1023 atoms of carbon
0,39 moles of gallium contain 2,34863493423.10e23 atoms.
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
The answer is 2,7 moles.
Using avagadro's number of 6.022 x 10 to the 23rd atoms/mole. The answer is 1.99 moles of gold
4.65Mol
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
1.20x10^24 atoms x 1 mole/6.02x10^23 atoms = 1.99 moles
The answer is 0,465 moles.
The answer is 6,227 moles.
10.08 moles (there are six carbon atoms per molecule of C6H6, hence, six times the number of moles of carbon can be produced).
1,638 moles contain 9,864266723766.10e23 atoms.
44 moles of atoms
1.51 X 1015 atoms (1 mole/6.022 X 1023) = 2.51 X 10 -9 moles ===============