Here is the balanced chemical equation, producing the right compounds of NO2 and H20:
Cu + 4HNO3 --> Cu(NO3)2 + 2NO2 + 2H2O
If the copper nitrate formed is copper (I) nitrate, the equation balances with one atom of each metal and one formula weight of each nitrate. If the copper nitrate formed is copper (II) nitrate, the balanced equation is: 2 AgNO3 + Cu -> 2 Ag + Cu(NO3)2.
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
Copper(II) hydroxide, when heated, decomposes to form copper(II) oxide and water. The balanced equation for this reaction is: 2Cu(OH)2(s) -> 2CuO(s) + H2O(g)
When you heat copper hydroxide and sodium nitrate, a chemical reaction occurs where the copper hydroxide decomposes to form copper oxide and water, while the sodium nitrate decomposes to form sodium nitrite, oxygen gas, and nitrogen dioxide gas.
Solutions of copper (II) compounds will undergo precipitation reactions with sodium hydroxide solution when mixed together to produce a bright blue precipitate of copper (II) hydroxide and a solution of a sodium salt.The chemical equations for the reaction between Copper (II) nitrate and Sodium hydroxide are as follows:Cu(NO3)2 (aq) + 2NaOH (aq) → Cu(OH)2 (s) + 2NaNO3 (aq)Copper II nitrate + sodium hydroxide → copper II hydroxide + sodium nitrate
One balanced equation for the reaction between elemental copper and silver nitrate is Cu + AgNO3 -> CuNO3 + Ag.
The balanced equation for the reaction between silver nitrate (AgNO3) and copper nitrate (Cu(NO3)2) is: 2AgNO3 + Cu -> Cu(NO3)2 + 2Ag
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
If the copper nitrate formed is copper (I) nitrate, the equation balances with one atom of each metal and one formula weight of each nitrate. If the copper nitrate formed is copper (II) nitrate, the balanced equation is: 2 AgNO3 + Cu -> 2 Ag + Cu(NO3)2.
Your balanced chemical equation for this double replacement reaction would be: Cu(NO3)2 + 2KOH ----> Cu(OH)2 + 2KNO3 Therefore, you would end up with copper II hydroxide and potassium nitrate.
No. It is a chemical change (chemical reaction) in which the products are different from the reactants. The balanced chemical equation is Cu(NO3)2+2NH4OH-->Cu(OH)2+2NH4NO3, which means one mole of copper(II) nitrate plus two moles of ammonium hydroxide produce one mole of copper(II) hydroxide plus two moles of ammonium nitrate.
The balanced equation for the reaction between copper(II) hydroxide (Cu(OH)2) and sulfuric acid (H2SO4) is Cu(OH)2 + H2SO4 → CuSO4 + 2H2O.
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
Copper(II) hydroxide, when heated, decomposes to form copper(II) oxide and water. The balanced equation for this reaction is: 2Cu(OH)2(s) -> 2CuO(s) + H2O(g)
When you heat copper hydroxide and sodium nitrate, a chemical reaction occurs where the copper hydroxide decomposes to form copper oxide and water, while the sodium nitrate decomposes to form sodium nitrite, oxygen gas, and nitrogen dioxide gas.
The balanced chemical equation for copper II nitrate (Cu(NO3)2) reacting with sodium chloride (NaCl) is: Cu(NO3)2 + 2NaCl -> CuCl2 + 2NaNO3. This equation is balanced as the number of atoms for each element is the same on both sides of the equation.