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No you cannot apply, as the circuit is open, there is no flow of charge or current, consequently the potential drop across the resistances would be zero

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Q: Can you apply KVL and KCL in an open or short circuits?
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Related questions

What is the difference while applying kcl to dc and ac circuits?

KCL is Common to both AC and DC. Only the waveform or AC and DC will differ


Can kcl and kvl be applied in ac and dc both?

Yes. Kirchhoff's laws (current and voltage) are the laws of nature for electrical and electronic circuits.


Can you apply kcl and kvl in ac and dc both why?

You can apply KCL (Kirchhoff's Current Law) and KVL (Kirchhoff's Voltage Law) in both AC and DC analysis. It just gets complicated in AC, because now you have to consider capacitive and inductive reactance, phase angle, power factor, etc. Even in a purely resistive circuit, one without capacitors or inductors, you need to consider AC analysis techniques if the frequency is sufficiently high, because of parasitic reactance that is always present. Kirchhoff's laws are the laws of nature for electrical and electronic circuits.


What is the mole ratio for KCl?

KCl


What is KCl?

KCL is Potassium Chloride.


How many moles of KCl are contained in 0.635L of 2.2M KCl?

moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl


How many ml of 0.25M KCl are needed to provide 0.012 moles of KCl?

0.012mol KCl x (1L/0.25mol KCl) x (1000ml/1L) = 48 mL KCl


How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?

moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl


What volume of 0.060 M KCl solution contains 2.39g of KCl?

MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L


What is the compound for KCl?

I'm guessing you meant KCl or potassium chloride.


How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?

Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed


What is the solubility of KCl in DMF?

KCl is soluble in DMF