Boric acid is weak base so how can be it titrate with strong base? To make this possible we mix glycerol to boric acid which make it strongly acidic and hence titration occure
Pyrogallic acid and sodium hydroxide is used to provide anaerobiosis.
Sodium Hydroxide + Hydrocloric acid --> Sodiumchloride + Water
The reaction between malic acid and sodium hydroxide can be represented as: C4H6O5 (malic acid) + NaOH → C4H6O5 (sodium malate) + H2O
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
There is no reaction. "Hydroxide acid" is water, which does not react with sodium hydroxide.
The word equation for the reaction of sulfuric acid and sodium hydroxide is: sulfuric acid + sodium hydroxide → sodium sulfate + water.
When boric acid and sodium hydroxide react, they form sodium borate, water, and heat is released. This reaction is exothermic and is commonly used in chemical experiments to understand acid-base reactions.
Sodium hydroxide plus hydrochloric acid equals sodium chloride plus water.
The balanced equation for the reaction between a fatty acid (such as oleic acid) and sodium hydroxide is: Fatty acid + Sodium hydroxide -> Soap (sodium salt of the fatty acid) + Water
Pyrogallic acid and sodium hydroxide is used to provide anaerobiosis.
To prepare sodium borate (Na3BO3), you would typically dissolve boric acid (H3BO3) in sodium hydroxide (NaOH) solution, followed by evaporation of water to yield the solid sodium borate. Care should be taken during the process as boric acid is a mild irritant and sodium hydroxide is caustic.
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
Stearic Acid + Sodium Hydroxide = Sodium Stearate (soap) + Water. C18H36OOH + NaOH = C18H36OONa + H2O
HCI
Sodium Hydroxide + Hydrocloric acid --> Sodiumchloride + Water
Di-carboxylic acid (such as oxalic acid) neutralizes with sodium hydroxide to form sodium salt of the di-carboxylic acid and water. The general word equation is di-carboxylic acid + sodium hydroxide -> sodium di-carboxylate + water.
The reaction of acetic acid and sodium hydroxide will form sodium acetate and water. The chloroform is not involved in the reaction and will remain unchanged. The balanced chemical equation for the reaction is: CH3COOH (acetic acid) + NaOH (sodium hydroxide) -> CH3COONa (sodium acetate) + H2O (water)