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Heating zinc sulfide in the prescence of oxygen yields th following 2zns 3o2---2zno 2so2 if 1.72 mol of zns is heated in the prescence of 3.04 mol of o2 which reactant will be used up first?
Wiki User
∙ 16y ago
The equation that you need is 2ZnS + 3O2 ======> 2ZnO + 2SO2
The equation is a 2 to 3 molar. The coefficients in the equation tell you how many moles of each reactant you need. So as the equation is 2ZnS + 3O2 that means 2 moles of ZnS is needed to react with 3 moles of O2. Since the question gives you 1.72 moles of ZnS and 3.04 moles of O2 the ZnS will run out first as 1.72 divided by 2 is 0.86 and 3.04 divided by 3 is 1.0133333... therefore we have less ZnS
Wiki User
∙ 15y ago
Wiki User
∙ 16y ago1.72 mol ZnS * 3 mol O2 = 2.58 mol O2 ---- 2 mol ZnS
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