A mole is 6.022*10^23 of a substance. An element's Atomic Mass, the number below the element's atomic symbol on the Periodic Table, is the number of grams one mole of that substance weighs. Multiply the number of moles of substance (here, 40 if you meant 40 moles or .04 if you meant millimoles) by the atomic mass of the substance (here, sodium's is 22.98977) to get the final answer in grams.
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The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
27 g Na + H2O = 40 g NaOH + 3 g H2. Law of Conservation of Mass. The reactants must have the same number of grams of the products. 40 + 3 = 43. 43 - 27 = 16 g H2O.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
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Sodium hydroxide (chemical composition NaOH) has an atomic mass of 40 amu which is also 40 grams/mole
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
40 kg = 40 000 gTo convert from kg to g, multiply the given value by 1000.
27 g Na + H2O = 40 g NaOH + 3 g H2. Law of Conservation of Mass. The reactants must have the same number of grams of the products. 40 + 3 = 43. 43 - 27 = 16 g H2O.
The answer is 2337,59 g NaCl.
There are 1,000,000 micrograms in a gram. You have to divide by a million here to convert. 24/1000000 will give you 0.000024 grams.
392.28 newtons or 88.2 pounds.
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
40 000 mg = 40 gTo convert from mg to g, divide by 1000. 40 000 mg = 0.04 kgTo convert from mg to kg, divide by 1 000 000.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How is 40g not a measurable unit? With a weighing scale it can be measured.