1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 35 moles of CO2, there would be 35 x 6.02 x 1023 molecules of CO2. In each CO2 there are three atoms (one carbon and two oxygen). Therefore the total number of atoms in 35mol of CO2 is 3 x 35 x 6.02 x 1023 = 6.32 x 1025
3.85 X Avogadro's number = 2.32 X 1024 atoms, to the justified number of significant digits.
The molar mass of carbon dioxide (CO2) is 44 g/mol. Carbon has a molar mass of 12 g/mol and oxygen has a molar mass of 16 g/mol. So, in 44g of CO2, there are 12g of carbon. Therefore, the percent by mass of carbon in 44g of carbon dioxide is (12g / 44g) x 100 = 27.3%.
The questions asks how many moles of carbon atoms.Molar mass is defined as the mass of one mole of a substance or in this case 6.022x1023 atoms of carbon. So the molar mass for carbon is 12.0 g/mol. Therefore the number of moles of carbon atoms is just 36/12.0 = 3.0 moles of carbon.How many atoms are in 36 grams of Carbon?[36 (gC) /12.0 (gC/molC)] * 6.02*10+23 (atoms C/molC) = 1.8*10+24 atoms in 36 g Carbon
The total moles of gas in the mixture is 0.25 + 0.75 + 1.5 = 2.5 mol. The mole fraction of carbon dioxide gas is the moles of CO2 divided by the total moles of gas, which is 1.5 mol / 2.5 mol = 0.6. So, the mole fraction of carbon dioxide gas in the mixture is 0.6.
44.010 g/mol You can sum up atomic weight of 1 carbon and 2 oxygen to this figure.
There are approximately 4.52 x 10^23 atoms in 0.750 mol of carbon monoxide. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of carbon monoxide (0.750 mol).
6.32 mol carbon dioxide
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
To calculate the percentage of oxygen in carbon dioxide, you can use the molecular formula of carbon dioxide (CO2), which consists of one carbon atom and two oxygen atoms. The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for carbon and 2 * 16.00 g/mol for oxygen). To find the percentage of oxygen in CO2, divide the molar mass contribution of oxygen (32.00 g/mol) by the molar mass of CO2 (44.01 g/mol) and multiply by 100. The percentage of oxygen in carbon dioxide is approximately 72.7%.
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C)7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms
There are approximately 5.84 x 10^21 carbon atoms in 9.7 x 10^-3 mol of carbon. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of carbon given.
3.85 X Avogadro's number = 2.32 X 1024 atoms, to the justified number of significant digits.
The density of a gas is proportional to its molecular mass. Nitrogen (N2) contains 2 nitrogen atoms each with a mass of about 14 AMU (atomic mass units) for a total molecular mass of about 44. Carbon dioxide (CO2) contains 2 atoms of oxygen, each with a mass of about 16 AMU and 1 carbon atom with a mass of about 12 AMU for a total mass of 44.
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
To calculate the percentage of oxygen in carbon dioxide, you can use the molar masses of carbon and oxygen. The molar mass of carbon dioxide is 44 g/mol (with 32 g/mol from O2 and 12 g/mol from C), and the molar mass of oxygen is 32 g/mol. Therefore, the percentage of oxygen in carbon dioxide is (32 g/mol / 44 g/mol) * 100 = 72.7%.
So CO2 is 44g/mol. 48/44 is 1.0909091 moles. This multiplied by avagadros number is 6.57x1023 molecules. As there is 1 carbon per molecule, this also equals the number of carbon atoms
There are 1 mole of carbon atoms in 12g of carbon. This is because the molar mass of carbon is 12 g/mol, so 12g of carbon is equivalent to 1 mole of carbon atoms.