The gram Atomic Mass of hydrogen is close to 1, so that 1 g of the gas contains one mole of hydrogen atoms. Each atom contains 1 electron, so that the stated amount of gas contains Avogadro's Number of electrons, 6 X 1023 to the justified number of significant digits.
About 1 mole
Amount of hydrogen gas = 1.0/2.0 = 0.50mol In each molecule of hydrogen gas there are two hydrogen atoms. 1 mol of H2 contains 6.02 x 1023 molecules (avogadro constant). Number of H atoms = 2 x 0.50 x 6.02 x 1023 = 6.02 x 1023
2
1% solution of KOH contains 1g of KOH in 100g of solution. This means that you need to mix 1g of KOH and 99g of water.
1g
About 1 mole
Amount of hydrogen gas = 1.0/2.0 = 0.50mol In each molecule of hydrogen gas there are two hydrogen atoms. 1 mol of H2 contains 6.02 x 1023 molecules (avogadro constant). Number of H atoms = 2 x 0.50 x 6.02 x 1023 = 6.02 x 1023
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
hydrogen-1g nitrogen-14g oxygen-16g
Yes. One mole (6.022x1023) of hydrogen atoms would have a mass of about 1g.
1
Since molar mass of hydrogen is 1g , the no. of moles = mass of hydrogen given. or No. of moles= Given mass of substance/Molar mass of substance
it is equal because 1g
They all contain electrons, protons, and neutrons. They are always neutral, or they would be Ions (I-ons) They have quarks that make up all or the protons and neutrons and electrons there are 623 billion atoms in 1g of hydrogen and 4g of helium and 7g of lithium ect 623 billion=1 mol
Rms= sqrt(((3)(8.314)(273.15k))/(1g/mole)) = 82.54 is the speed of one hydrogen molecule. Assuming stp
One pound = 0.453592kg. One Mole of H = 1g 0.453592kg of H = 453.592 mole of H According to the ideal gas law, one mole of gas will occupy 22.4 liters as stp. One pound of H will occupy 10,160.2608 liters, or 358.806 cubic feet. Be careful. Most applications of this calculation will deal with hydrogen gas, which has two hydrogen atoms per molecule at standard temperature and pressure. In such cases, divide the volume calculated above by two.
Helium diffuses twice faster as Methane does.