Atomic Mass of Na is 23.0. This means that the mass of 1 mole of sodium is 23.0g.
Mass of 4.5mol of Na = 4.5 x 23.0 = 103.5g
To calculate the number of grams in 2.50 moles of H2O, you first need to know the molar mass of water (H2O), which is approximately 18.015 g/mol. Then, you can use the formula: grams = moles x molar mass. So, 2.50 moles of H2O is equivalent to 45.04 grams (2.50 moles x 18.015 g/mol).
It is a solution whose strength and quantity are given .
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.
45/94.2 is 0.4777 moles
To calculate the number of grams in 2.50 moles of H2O, you first need to know the molar mass of water (H2O), which is approximately 18.015 g/mol. Then, you can use the formula: grams = moles x molar mass. So, 2.50 moles of H2O is equivalent to 45.04 grams (2.50 moles x 18.015 g/mol).
45 mg contains approximately 1.956 moles of atomic sodium.
It is a solution whose strength and quantity are given .
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
First of all we convert the mass of leadto moles. Using the equation moles = mass(g) / Ar (Realtive atomic Mass)_. Mass( g) = 45 g Ar =~ 207 (Periodic Table). Hence moles(Pb) = 45 x 207 Moles (Pb) = 9315 moles. Next using the Avogadro number. 1 moles(of A SUBSTANCE) contains 6.022 x 10^(23) atoms. Hence number of atoms in 9315 moles = 9315 x 6.022 x 10^(23) = 5.61 x 10^(27) atoms. As a 'silly' number. 5,610,000,000,000,000,000,000,000,000 atoms.
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
45 g water are obtained.
There's a thousand grams in a kilogram, 45 grams is 0.045 kilograms.
0.045 grams is 45 milligrams.
450 grams
1kg = 1000g. Therefore, 45 x 1000 = 45000 grams.