It is quit simple. Calculate the molar mass of calcium nitrate using your Periodic Table and multiple by 12.3. Use this simple formula
N = m / M
N = number of mols
m = mass in grams
M = molar mass of the substance (grams / mol)
Note to find molar mass of the molecule add up the atomic masses of the individual element (ie : Carbon is 12.01 g/mol) be sure to multiply by how many individual atoms of a element are in your molecule or substance.
In your case Ca(NO3)2
1 Ca
2 N
6 O
Hope this is what you needed
First find the atomic weight of the molecule calcium nitrate, Ca(NO3 )2 .
Ca=40.08
N=14 x2=28
O=16 x6=96
Ca(NO3)2 = 164.08 g/mol
With that you can convert the 1 mole of calcium nitrate into grams.
1 mol x 164.08 g/mol = 164.08 g calcium nitrate
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
Ca(NO3)2 5.600 grams calcium nitrate ( 1mole Ca(NO3)2/164.1 grams)(2 moles NO3/1 mole Ca(NO3)2) = 6.825 X 10 -2 moles of nitrate ions -----------------------------------------------
80.02 grams
129 grams calcium (1 mole Ca/40.08 grams calcium)(6.022 X 10^23calcium atoms/1 mole Ca) = 1.94 X 10^24 atoms of calcium
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
4.563 grams are in 1 mole of Strontium Nitrate.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
80.02 grams
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
Ca(NO3)2 5.600 grams calcium nitrate ( 1mole Ca(NO3)2/164.1 grams)(2 moles NO3/1 mole Ca(NO3)2) = 6.825 X 10 -2 moles of nitrate ions -----------------------------------------------
80.02 grams
Quite a few! 175 grams calcium (1 mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca) = 2.63 X 10^24 atoms of calcium -------------------------------------------
129 grams calcium (1 mole Ca/40.08 grams calcium)(6.022 X 10^23calcium atoms/1 mole Ca) = 1.94 X 10^24 atoms of calcium
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============