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The specific heat capacity of water between 25 C and 100 C is 4.1813 J / (g*K).

Beyond 100 C, the heat capacity of water is 2.080 J / (g*K)

So, it take 4.1813 joules of energy to heat 1 gram of water 1 degree Celsius (Kelvin).

Therefore, in order to heat 22 g of water from 25 C to 100 C (75 C), it would require:

4.1813 * 22 * 75 = 6899.145 J

And, to heat 22 g of steam from 100 C to 125 C (25 C), it would require:

2.080 * 22 * 25 = 1144 J

The combined amount of energy required would be:

6899.145 + 1144 = 8043.145 J

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