The formula given shows that equal numbers of atoms of sodium and of chloride are needed to constitute one formula mass of NaCl. Therefore, 6.2 formula mass amounts of NaCl can be produced from 6.2 mol "Cl"* if at least 6.2 mol Na is also available.
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*Elemental chlorine normally occurs as diatomic molecules. However this question is answered in accordance with its own statement. 6.2 mol Cl would constitute 3.1 mol Cl2, but the answer would still be the same, because the same number of chlorine atoms would be provided for the reaction
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
The mole fraction of NaCl in the solution is calculated by dividing the moles of NaCl by the total moles of NaCl and water. In this case, the mole fraction of 18 mol NaCl in a solution of 100 mol water is 0.15 (18 mol NaCl / (18 mol NaCl + 100 mol water)).
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
The mole fraction of NaCl in the solution is calculated by dividing the moles of NaCl by the total moles of NaCl and water. In this case, the mole fraction of 18 mol NaCl in a solution of 100 mol water is 0.15 (18 mol NaCl / (18 mol NaCl + 100 mol water)).
When salt (NaCl) is split by electrolysis, one mole of sodium (Na) and one mole of chlorine (Cl2) gas are produced. The molar mass of NaCl is 58.44 g/mol, so 40.0 g of NaCl is approximately 0.68 moles. Therefore, 0.68 moles of chlorine gas are produced.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
One mole of AgNO3 reacts with one mole of NaCl to form one mole of AgCl precipitate. Therefore, 0.100 mol of AgNO3 will form 0.100 mol of AgCl precipitate when reacted with excess NaCl.
I'll see if I can type it out for you.. 79g NaCl x (1 mol NaCl)/(58.44g NaCl) = 1.35 mol NaCl 1 mol NaCl = 58.44g (because Na is 22.99g and Cl is 35.45g)
1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
To find the number of moles in 234g of NaCl, divide the given mass by the molar mass of NaCl. The molar mass of NaCl is 58.44 g/mol (sodium = 22.99 g/mol, chlorine = 35.45 g/mol). So, 234g ÷ 58.44 g/mol = 4 moles of NaCl.
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
By definition, one mole would be the same as the atomic mass or molecular mass. You take the number of moles and multiply it by the molecular mass (divide by one mole for units to cancel). So if you have just 1 mole, the number of grams will just be the molecular mass. The molecular mass is the atomic masses of the elements in the compound added together.Na- 23.0Cl- 35.5NaCl- 58.5 grams in one mole
the molar mass of sodium is 23 and chlorine is 35 so they add together to create 58 grams per mole. So 5.58g/58g=.0962 moles.