.0000787 mol
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
To find the number of moles of ammonia gas, first convert the volume to liters (202 mL = 0.202 L). Then use the ideal gas law (PV = nRT) to calculate the number of moles. Given that the temperature is 35°C (308 K) and the pressure is 750 mmHg (0.987 atm), you can rearrange the ideal gas law to solve for moles (n = PV/RT). Plugging in the values, n = (0.987 atm * 0.202 L) / (0.0821 L·atm/mol·K * 308 K) = 0.00851 moles of ammonia gas.
this is a easy one. There are only 0.04166 moles.
To find the number of moles in 170000 grams of ammonia, you need to divide the given mass by the molar mass of ammonia. The molar mass of ammonia (NH3) is about 17 grams/mol. Therefore, 170000g ÷ 17g/mol ≈ 10000 moles of ammonia.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
8,038 moles of ammonia were produced.
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
To find the number of moles of ammonia gas, first convert the volume to liters (202 mL = 0.202 L). Then use the ideal gas law (PV = nRT) to calculate the number of moles. Given that the temperature is 35°C (308 K) and the pressure is 750 mmHg (0.987 atm), you can rearrange the ideal gas law to solve for moles (n = PV/RT). Plugging in the values, n = (0.987 atm * 0.202 L) / (0.0821 L·atm/mol·K * 308 K) = 0.00851 moles of ammonia gas.
To calculate the number of moles of ammonia gas in a 1 mL container at a certain temperature and pressure, you first need to convert the pressure to atm if you're using ideal gas law, and then use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Remember to convert the volume to liters and the temperature to Kelvin for accurate calculations.
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.