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How many moles of chloride ions are in 3.12 moles of ZnCl2?
DaltonGola
In exactly one gram formula unit, there are always Avogadro's Number of individual formula units. Therefore, the number of gram moles or gram formula units in 3.61 X 1023 formula units is* 3.61/6.022 or 0.599, to the justified number of significant digits.
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The factor 1023 occurs in both numerator and denominator and therefore need not be written.
Wiki User
∙ 10y ago
Wiki User
∙ 9y ago3.58 E23 formula units is equal to 3.58 E23 molecules of ZnCl2. There are 6.022 E23 atoms in a mole, so there are 0.5945 moles present.
Wiki User
∙ 11y ago6.02x10(to the power of 23). This is the calculation of 1 mol. Use this to times the 3.12 moles of ZnCl2. Then times the 2 atoms of Cl2. The answer is 3.75648x10(to the power of 24).
Wiki User
∙ 12y ago0.59448688143474 assuming you meant 10^23 instead of 1023
Wiki User
∙ 9y agoWiki User
∙ 8y ago3,85 g zinc is equivalent to 0,059 moles.
Wiki User
∙ 11y ago0.595 mol ZnCl2
Wiki User
∙ 8y ago.65
Anonymous
55.45
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