0
In exactly one gram formula unit, there are always Avogadro's Number of individual formula units. Therefore, the number of gram moles or gram formula units in 3.61 X 1023 formula units is* 3.61/6.022 or 0.599, to the justified number of significant digits.
______________________________
The factor 1023 occurs in both numerator and denominator and therefore need not be written.
What else can I help you with?
How many moles of chloride ions are in 0.2520g of aluminum chloride?
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
How many chloride ions are there in 3 mol of aluminum chloride?
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
How many chloride ions are in sample of salt that contains 2 moles of MgCl2?
Two Chloride ions (2Cl-) ions are needed with their -1 charge on each one to cancel out the +2 charge of the single Magnesium ion (Mg2+). So Magnesium Chloride would have the chemical formula: MgCl2
How many chloride ions are present in 65.5 mL of 0.210 M AlCl3 solution?
In 1 mol of AlCl3, there are 3 chloride ions. First calculate the moles of AlCl3 in the solution: 65.5 mL is 0.0655 L. Multiply 0.0655 L by 0.210 mol/L to get the moles of AlCl3. Finally, multiply this by 3 to find the number of chloride ions in the solution.
How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
How many chloride ions are in a sample of salt that contains 2 moles of KCl?
There are 2 moles of KCl in the sample, so there are 2 moles of chloride ions as well. Since each molecule of KCl contains 1 chloride ion, there are 2 moles of chloride ions in total.
How many moles of chloride ions are in 0.2520g of aluminum chloride?
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
How many moles of ions AL3 and how many mols of ions CL-has in 0.9 mols of ALCL3?
I suppose that the answers are: - 0,9 moles aluminium ions - 2,7 moles chloride ions
How many chloride ions are in a sample of salt that contains 2 moles of MgCl2?
2.4088 x 1024 chloride ions
How many ions or atoms of calcium and chloride in 1.5 moles of CaCl2?
In 1.5 moles of CaCl2, you would have 3 moles of ions or atoms of calcium and 3 moles of ions of chloride. Since CaCl2 dissociates into 1 calcium ion (Ca2+) and 2 chloride ions (2Cl-), this means you would have 3 moles of calcium ions and 6 moles of chloride ions in total.
How many chloride ions are there in 3 mol of aluminum chloride?
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
How many chloride ions are in sample of salt that contains 2 moles of MgCl2?
Two Chloride ions (2Cl-) ions are needed with their -1 charge on each one to cancel out the +2 charge of the single Magnesium ion (Mg2+). So Magnesium Chloride would have the chemical formula: MgCl2
How many chloride ions are in calcium chloride?
The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.
How many chloride ions are present in 65.5 mL of 0.210 M AlCl3 solution?
In 1 mol of AlCl3, there are 3 chloride ions. First calculate the moles of AlCl3 in the solution: 65.5 mL is 0.0655 L. Multiply 0.0655 L by 0.210 mol/L to get the moles of AlCl3. Finally, multiply this by 3 to find the number of chloride ions in the solution.
How many grams of zinc chloride can be formed from the reaction of 7.96 g of zinc with excess HCl?
The equation for the reaction is Zn + 2 HCl -> ZnCl2. The gram atomic masses of zinc and chlorine are 65.39 and 35.453 respectively. Therefore, the number of grams of zinc chloride that can be formed from 7.96 g of zinc is: 7.96{[65.39 + 2(35.453)]/65.39} or about 16.6 g of zinc chloride, to the justified number of significant digits.
How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
How many chloride ions are in a sample of salt that contains one mole of CaCl2?
In one mole of CaCl2, there are 2 moles of chloride ions since there are 2 chloride ions for every 1 CaCl2 molecule. Therefore, there are 2 * 6.022 x 10^23 = 1.2044 x 10^24 chloride ions in one mole of CaCl2.
