molar weight of N = 14 grams/mole
35.7 grams/14 grams/mole = 2.55 moles
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.
The number of moles in 11.2 liters of nitrogen gas (N2) can be calculated using the ideal gas law. Since you have two nitrogen atoms per molecule of N2, you would need to convert the volume of gas to moles using the ideal gas constant.
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
3.6
Three moles of electrons are required to reduce one mole of nitrogen gas N2 to two moles of nitrogen ions N3-. This is because each nitrogen molecule N2 gains 3 electrons to form two nitrogen ions N3-.
There are 1 mole of nitrogen gas molecules contain 2 nitrogen atoms. Therefore, 0.25 mole of nitrogen gas would contain 0.25 * 2 = 0.5 moles of nitrogen atoms.
To determine the number of nitrogen molecules in 12.88g of nitrogen gas, you first need to convert grams to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to find the number of molecules in that number of moles.
To determine the number of molecules in 140g of nitrogen gas, you first need to convert the mass of nitrogen gas to moles using its molar mass. The molar mass of nitrogen gas (N2) is 28 g/mol. Once you have the number of moles of nitrogen gas, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules present in 140g of nitrogen gas.
PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.
To determine the number of moles of nitrogen and oxygen in a given volume like a cubic foot, you would first need to know the pressure and temperature of the gas. Then you can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. So without knowing the pressure and temperature, it is not possible to determine the number of moles of nitrogen and oxygen in a cubic foot.
The number of moles in 11.2 liters of nitrogen gas (N2) can be calculated using the ideal gas law. Since you have two nitrogen atoms per molecule of N2, you would need to convert the volume of gas to moles using the ideal gas constant.
To calculate the number of moles of nitrogen gas in the container, you can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Convert the pressure to atm, the volume to L, and the temperature to Kelvin. Then plug in the values and solve for n.