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The vapor pressure of 1 m NaCl is lower than the vapor pressure of 0.5 m KNO3 assuming that the solvent in each case is water?
This is because NaCl is a strong electrolyte that dissociates completely into ions in water, leading to more solute particles that disrupt vapor pressure. In contrast, KNO3 is a weak electrolyte that partially dissociates, resulting in fewer solute particles and less disruption of vapor pressure.
Calculate the isotonic coefficient for NaCl if a 07M of NaCl solution equaled the hemolysis of14M glucose solution?
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
How could you make a 1.00M solution if you had a 2.00M solution of NaCl?
To make a 1.00M NaCl solution from a 2.00M solution, you can dilute the 2.00M solution by adding an equal volume of solvent (like water). For example, mix 1 cm^3 of the 2.00M solution with 1 cm^3 of water to create a 1.00M solution.
What is the molarity of the solution where 0.5 g of NaCl is dissolved to make 0.05 L of solution?
Given: 0.5 g NaCl; 0.05 L of solution.1) Find the molar mass of NaCl.(22.99) + (35.45) = 58.44 g/mol of NaCl2) Convert grams of NaCl to moles of NaCl.(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl3) Use the molarity equation, M = mol / L, to solve for molarity (M).(0.00855578 mol NaCl / 0.05 L) = 0.17 M
Which will have the lowest boiling point pure water 0.5 M NaCl aq 1.0 M NaCl aq or 2.0 M NaCl aq?
Pure water will have the lowest boiling point because it does not contain any solute particles to elevate the boiling point. As the concentration of NaCl increases, the boiling point also increases due to an increase in the number of solute particles that disrupt the formation of water vapor. Therefore, 0.5 M NaCl will have a higher boiling point than pure water, followed by 1.0 M NaCl, and finally 2.0 M NaCl will have the highest boiling point.
preparation of 0.1 m of NaCL ML SOLUTION AND ITS LAP REPORT?
A solution of NaCl 1 M.
The vapor pressure of 1 m NaCl is lower than the vapor pressure of 0.5 m KNO3 assuming that the solvent in each case is water?
This is because NaCl is a strong electrolyte that dissociates completely into ions in water, leading to more solute particles that disrupt vapor pressure. In contrast, KNO3 is a weak electrolyte that partially dissociates, resulting in fewer solute particles and less disruption of vapor pressure.
What is the mole concentration of 58.44g of NaCl in 1 L of water?
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
You want 1 liter of 0.1 M NaCl and you have 4 M stock solution How much of the 4 M solution and how much dH2O will you measure out for this dilution?
To make 1 liter of 0.1 M NaCl solution, you will need 25 ml of the 4 M NaCl stock solution and 975 ml of water. This will give you the desired concentration of 0.1 M NaCl in a total volume of 1 liter.
Is 5 M glucose an electrolyte?
Glucose is not an electrolyte in solution.
What is 5 M of NaCl equivalent to?
5 M of NaCl is equivalent to 292,2 grams.
What is the total dilution factor from 1.00 M NaCl to 1.00 M NaCl solution?
The concentration is the same !
How many milliliters of 2 M NaCl solution are required to make 1 liter of 0.4 M NaCl solution?
To make 1 liter of 0.4 M NaCl solution, you would need 200 mL of 2 M NaCl solution. This can be calculated using the formula Mi x Vi = Mf x Vf, where Mi is the initial molarity, Vi is the initial volume, Mf is the final molarity, and Vf is the final volume.
True or false The vapor pressure of 1 m sucrose is higher than the vapor pressure of 1 m NaCl where the solvent is water?
maybe
If you have 2 liters of 2 M NaCl you take 500 ml of that and add it to 500ml of pure water the new 1000 ml preparation is now?
A solution of NaCl 1 M.
Calculate the isotonic coefficient for NaCl if a 07M of NaCl solution equaled the hemolysis of14M glucose solution?
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
How could you make a 1.00M solution if you had a 2.00M solution of NaCl?
To make a 1.00M NaCl solution from a 2.00M solution, you can dilute the 2.00M solution by adding an equal volume of solvent (like water). For example, mix 1 cm^3 of the 2.00M solution with 1 cm^3 of water to create a 1.00M solution.
