CuCl2 + H2S --> CuS + 2HCl
Yes, this is the balanced equation here.
CuCl2(aq) + K2S(aq) --> CuS(s) + 2KCl(aq) K and Cl are spectators so the net ionic would be: Cu2+(aq) + S2-(aq) --> CuS(s)
To determine the limiting reactant, first calculate the moles of each reactant by dividing the given mass by their respective molar masses. Then, determine the mole ratio between CuS and O2 in the balanced chemical equation. The reactant that produces fewer moles of product based on this ratio is the limiting reactant.
Here is the balanced chemical equation, producing the right compounds of NO2 and H20:Cu + 4HNO3 --> Cu(NO3)2 + 2NO2 + 2H2ORead more: What_is_the_balanced_chemical_equation_for_when_solid_copper_is_added_to_nitric_acid_copper_2_nitrate_nitrogen_dioxide_and_water_are_produced
2CuS + 3O2 ---> 2CuO + 2SO2 Copper Sulphide + Oxygen ---> Copper Oxide + Sulphur dioxide
There's nothing to drive the reaction, since all the possible combinations are soluble. Before, you would have copper, sodium, chloride and sulfate ions in solution; after, you would have the same thing. It's not really a reaction if nothing happens.
The reaction between CuCl2 (copper(II) chloride) and H2S (hydrogen sulfide) is a double displacement reaction. The balanced chemical equation is: CuCl2 + H2S -> CuS + 2HCl The products formed are CuS (copper(II) sulfide) and 2HCl (hydrochloric acid).
These compounds are CuSO3 CuS CuCl2..
CuCl2(aq) + K2S(aq) --> CuS(s) + 2KCl(aq) K and Cl are spectators so the net ionic would be: Cu2+(aq) + S2-(aq) --> CuS(s)
The balanced chemical equation for the reaction between H2S (hydrogen sulfide) and CuSO4 (copper(II) sulfate) is: H2S + CuSO4 → CuS + H2SO4 This equation is balanced as it shows the conservation of atoms of each element on both sides of the reaction.
The balanced equation for the reaction is: 2 Na2S (s) + 3 Cu(NO3)2 (aq) -> 4 NaNO3 (aq) + 3 CuS (s)
To calculate the molar solubility of copper(II) sulfide, you need to consider the solubility product constant (Ksp) of CuS. Once you have the Ksp value, set up an equilibrium expression for the dissociation of CuS into Cu^2+ and S^2- ions. Use the initial concentration of CuCl2 to determine the concentration of Cu^2+ ions and then solve for the molar solubility of CuS.
To determine the limiting reactant, first calculate the moles of each reactant by dividing the given mass by their respective molar masses. Then, determine the mole ratio between CuS and O2 in the balanced chemical equation. The reactant that produces fewer moles of product based on this ratio is the limiting reactant.
For the molecular balance of the equation it would be: CuSO4 (aq) + Na2S (aq) = CuS (s) + Na2SO4 (aq). For the net ionic balance of the equation it would be: Cu2+ (aq) + S2(aq) = CuS (s).
equation = Cu + S -> CuS "law of conservation of mass" 80 + 25 = 105 g CuS formed
Here is the balanced chemical equation, producing the right compounds of NO2 and H20:Cu + 4HNO3 --> Cu(NO3)2 + 2NO2 + 2H2ORead more: What_is_the_balanced_chemical_equation_for_when_solid_copper_is_added_to_nitric_acid_copper_2_nitrate_nitrogen_dioxide_and_water_are_produced
The chemical equation is:Cu(NO3)2 + BaS = CuS(s) + Ba(NO3)2
2CuS + 3O2 ---> 2CuO + 2SO2 Copper Sulphide + Oxygen ---> Copper Oxide + Sulphur dioxide