older because it is at the bottom and the ones on top are younger than the bottoms
What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?A. The fault is older than the middle layer. B.The fault is younger than all the layers it cuts across.C. The fault is the same age as the top layer. D. The fault is older than all the layers it cuts across == ==
Younger than the layer below it.
The layers above the 120 million-year-old middle layer are likely younger, while the layers below are likely older. This indicates a relative chronological sequence in the deposition of the rock layers, following the principle of superposition in geology.
Xenoliths are blocks of older rock enclosed in a body of younger igneous rock.
She can infer that the rock layer with the fossil is younger than the layer without the fossil because the fossil was deposited after the formation of the rock layer. This provides a relative age relationship between the two layers.
To determine whether the fault is older or younger than rock layer A, we can use the principle of cross-cutting relationships. If the fault cuts through rock layer A, it is younger than that layer, as it must have formed after the rock was deposited. Conversely, if rock layer A is found to be disrupted by the fault, then the fault is older. Therefore, examining the relationship between the fault and rock layer A is key to establishing their relative ages.
"The fossils found in this rock layer are older than the fossils found in the layer above it." "The granite intrusion is younger than the surrounding sedimentary rocks." "The volcanic ash layer is slightly older than the layer of soil above it." "The erosion pattern on the hillside indicates that the granite rocks are older than the layers of sediment deposited on top of them." "The cross-cutting relationship between the fault and the layers of rock indicate that the fault is younger than the rock layers it cuts through."
One is not necessarily older than the other. It depends on the context. A fault running through any rock must be younger than that rock.
It is a law that the higher the rock layer is the younger it is. The deeper it is the older the rock layer is.
The layer of rock at the bottom of a sedimentary rock is older. This is due to the principle of superposition, which states that in an undisturbed sequence of rock layers, the oldest rocks are at the bottom and the youngest are at the top.
The process of "overthrusting" occurs when tectonic forces push one rock layer on top of another, causing younger rock to be placed beneath older rock. This can lead to a reverse order of rock layers in a geologic formation. Another process, called "faulting," involves the movement of rock layers along a fault plane, which can result in the displacement of younger rocks below older rocks.
The law of superposition states: in horizontal rock layers, each layer is older than the one above it and younger than the one below it.
What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?A. The fault is older than the middle layer. B.The fault is younger than all the layers it cuts across.C. The fault is the same age as the top layer. D. The fault is older than all the layers it cuts across == ==
When older rock ends up on younger rock When the Earth surface is pushed up along a crack or two.
Extrusion is older than intrusion because, an extrusion is always younger than the rocks below it. An intrusion is always younger than the rock layers around and beneath it. Hope the answers correct ;)
According to the geologic Law of Superposition, in undisturbed rock strata, the deepest rock layers are always the oldest. Accordingly, a fossil found in a lower layer of undisturbed rock would be the older.
Every layer of rock, as one moves up from the core, is younger than the one below it. This means that the layers of rock above and below the coal are different ages, with the one above younger and the one below older.