The reaction between magnesium nitrate and potassium chromate is a chemical change. 2KOH(aq) + Mg(NO3)2(aq) --> 2KNO2(aq) + Mg(OH)2(s)
The molecular equation for lead(II) acetate reacting with potassium chromate is: Pb(C2H3O2)2 + K2CrO4 -> PbCrO4 + 2KCH3COO
When potassium chromate and lead(II) acetate are mixed, they undergo a double displacement reaction to form lead(II) chromate (yellow precipitate) and potassium acetate. This reaction can be represented by the equation: Pb(C2H3O2)2 (aq) + K2CrO4 (aq) → PbCrO4 (s) + 2KCH3COO (aq).
the chemical reaction between silver nitrate and potassium chromate in generally used in a titration to look for chloride ions , and is a two step reaction: i will give you the ionic equations, which is pretty much all you need Ag+(aq) + Cl-(s) --> AgCl(s) this part of the equation caused the solution to go cloudy. when all the chloride ions are used up then the silver reacts with the chromate ions to produce the red colour you see when the end point of the precipitation is reached: 2Ag+(aq) + CrO4 2-(aq) --> Ag2 CrO4(s) which produces the red colour the amount of silver nitrate relates directly to the chloride ion concentration as it is a 1:1 ration reaction. i hope this answers your question =)
2Ag(aq)+ CrO4(s)---->AgCrO4(s)
It depends on the chemical reaction taking place.magnesium + oxygen -> magnesium oxideIn equation 1 it would be a reactant.magnesium oxide -> magnesium + oxygenIn equation 2 it would be a product.If magnesium is on the left-hand side of the equation it is a reactant.If magnesium is on the right-hand side of the equation it is a product.From Wikipedia:"The substances initially involved in a chemical reaction are called reactants. Chemical reactions are usually characterized by a chemical change, and they yield one or more products, which usually have properties different from the reactants."
When potassium chromate reacts with magnesium nitrate, a double displacement reaction occurs. Potassium nitrate and magnesium chromate are formed as products. This reaction is represented by the following equation: K2CrO4 + Mg(NO3)2 -> MgCrO4 + 2KNO3.
When potassium chromate (K₂CrO₄) reacts with strontium nitrate (Sr(NO₃)₂), a double displacement reaction occurs, resulting in the formation of strontium chromate (SrCrO₄) and potassium nitrate (KNO₃). The balanced chemical equation for this reaction is: [ K_2CrO_4 + Sr(NO_3)_2 \rightarrow SrCrO_4 + 2 KNO_3 ] Strontium chromate is a yellow precipitate, indicating the occurrence of the reaction.
The chemical equation for potassium is K.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium chromate (K2CrO4) is: Ag+ + 2NO3- + 2K+ + CrO42- -> Ag2CrO4(s) + 2KNO3 This reaction forms silver chromate (Ag2CrO4) as a solid precipitate, with potassium nitrate (KNO3) remaining in solution.
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
The molecular equation for lead(II) acetate reacting with potassium chromate is: Pb(C2H3O2)2 + K2CrO4 -> PbCrO4 + 2KCH3COO
The answer is:- MgCl2 + K2CO3 --> MgCO3 + 2KCl The products are potassium chloride and magnesium carbonate
the word chemical equation islead nitrate + sodium chromate --> sodium nitrate + lead chromate
The chemical equation for potassium perchlorate is KClO4.
The chemical symbol of potassium is K.
the word chemical equation islead nitrate + sodium chromate --> sodium nitrate + lead chromate
The chemical equation for magnesium iodide is MgI2. It is formed by the reaction between magnesium metal and iodine.