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Was it a conservative boundary that made the Kobe earthquake?

No, it was a destructive plate boundry. :)


Was the Kobe earthquake on a destructive margin?

Yes, the Kobe earthquake occurred along a destructive plate boundary where the Philippine Sea Plate subducted beneath the Eurasian Plate. This resulted in intense shaking and significant damage to infrastructure in the region.


What is the name of the earthquake which occurred in Kobe in 1923?

It was named The Great Hanshin earthquake or Kobe earthquake.


When did the Kobe earthquake occur and in which country can Kobe be found?

The Kobe earthquake occurred in Japan in the year 1995.


What year was the earthquake of Kobe in Japan?

The Earthquake of Kobe occurred in Japan in 1995.


Where did Kobe earthquake happen YER?

The Kobe earthquake occurred in Kobe, Japan in 1995. It was a magnitude 6.9 earthquake that caused extensive damage and loss of life in the region.


What plates caused the Kobe earthquake?

It was the Eurasian and the Philippine plates that moved and caused the earthquake in Kobe.


Cost of damage in Kobe earthquake?

The cost of the repairs for Kobe after the earthquake was at least 160 billion yen.


How did the Kobe earthquake affect Kobe?

it damaged lots of houses


What was the name for the earthquake in japan 1995?

Its called the Kobe earthquake


How much did it cost to fix Kobe after the Kobe earthquake?

$100 billion


What is the magnitude of an earthquake along a conservative margin?

Generally up to 8.5 on the Richter Scale but usually shallow too, down to 25km. Not the largest, but in the case of the San Andreas Fault, N American and Pacific Plates, the effects are largely publicised. The conservative margin is usually located under water/oceans.