Br2 + 2C5H10 = 2C5H8Br + 2H2
Pentene is an unstaturdated hydrocarbon (One that does not have many possible side branches) It reacts readily with halogens to form new substances. In this case, bromine reacts with pentene in an addition reaction, this changes pentene into 1,1-dibromopentane. Thus, removing bromine from the solution, hence the distinct orange color is removed.
CH3-CH=CH-CH2-CH3 + Br2 = CH3-CH(Br)-CH(Br)-CH2-CH3
C6H9.CH3 + Br2 ---------------> C6H7(Br)2CH3.
Formula: BrF3
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
do you go to mvcc
Pentene is an unstaturdated hydrocarbon (One that does not have many possible side branches) It reacts readily with halogens to form new substances. In this case, bromine reacts with pentene in an addition reaction, this changes pentene into 1,1-dibromopentane. Thus, removing bromine from the solution, hence the distinct orange color is removed.
1-bromo 1 pentene
CH3-CH=CH-CH2-CH3 + Br2 = CH3-CH(Br)-CH(Br)-CH2-CH3
C6H9.CH3 + Br2 ---------------> C6H7(Br)2CH3.
I cannot answer this question.
Bromine is not combustible
Bromine is an electrophile (electron deficient species) it attacks the Carbon doubble bond and accepts a pair of electrons. this is known as electrophillic addition. the equation is: C2H4 + Br2 - C2H4Br2 the product is 1,2 dibromoethane. this product is colourless.
Formula: BrF3
bromine water? The reaction between hexene, bromine, and water is an addition reaction.
The equation is, 2Al + 3Br2 = 2AlBr3
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr