Ca+2 PO4-3 <---- these are the ions and their charges
Ca+2 Ca+2 Ca+2 PO4-3 PO4-3 <---- the charges have to add up to zero, so three +2 calcium ions cancel out two -3 phosphate ions
Ca3(PO4)2 <---- simplify
The equivalent weight of calcium phosphate is calculated by dividing the molar mass of calcium phosphate by the valency factor of the phosphate ion. Since calcium phosphate is a salt with the formula Ca₃(PO₄)₂, its molar mass is calculated by adding the molar masses of calcium and phosphorus (since there are three calcium ions and two phosphate ions in the formula). The valency factor of phosphate ion is 2 since it can donate or accept 2 electrons.
Find the atomic mass of calcium phosphate [ Ca3(PO4)2 ]Ca3 = 120.3P2 = 62O8 = 128Total Atomic Mass = 310.3Moles= mass/atomic massMoles = 660/310.3Moles = 2.127M (Concentration) = moles/litresM= 2.127 mol/2.5LM= 0.8508Concentration = 0.8508M
Molar (formula) mass of calcium nitrate is 164,1 9/mol Molecular weight calculation: 40.078 + (14.0067 + 15.9994*3)*2
1. Calculate formula massCalcium carbonate has chemical formula CaCO3.Its formula mass is 40.1 + 12.0 + 3(16.0) = 100.12. Apply formula to calculate number of moles of CaCO3Amount of CaCO3= mass/formula mass= 50/100.1= 0.50mol
the mass of Ca3(PO4)2 is 310.18g This is because Calcium's mass is 40.08g and you have to times it by 3. Then you add phosphorus which is 30.97g times 2. Lastly, add oxygen's mass which is 16.00g times 8 because 4*2 is 8. (40.08g*3)+(30.97g*2)+((16.00g*4)*2)=310.18g
The equivalent weight of calcium phosphate is calculated by dividing the molar mass of calcium phosphate by the valency factor of the phosphate ion. Since calcium phosphate is a salt with the formula Ca₃(PO₄)₂, its molar mass is calculated by adding the molar masses of calcium and phosphorus (since there are three calcium ions and two phosphate ions in the formula). The valency factor of phosphate ion is 2 since it can donate or accept 2 electrons.
The formula mass of calcium phosphate (Ca3(PO4)2) is calculated by adding the atomic masses of each individual element in the compound. The atomic mass of calcium (Ca) is approximately 40.08 g/mol, phosphorus (P) is approximately 30.97 g/mol, and oxygen (O) is approximately 16.00 g/mol. Therefore, the formula mass of calcium phosphate is 3(40.08) + 2(30.97) + 8(16.00) = 310.18 g/mol.
To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
Calcium chloride with formula CaCl2 has molecular mass of 141. Commercial calcium chloride has formula CaCl2,2H2O.It's molecular mass is 177.
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
Balanced equation first. Ca3(PO4)2 + 3H2SO4 -> 3CaSO4 +2H3PO4 1.523 moles H2SO4 (1 mole Ca3(PO4)2/3 moles H2SO4)(310.18 grams/1 mole Ca3(PO4)2) = 157.5 grams of Calcium phosphate
Find the atomic mass of calcium phosphate [ Ca3(PO4)2 ]Ca3 = 120.3P2 = 62O8 = 128Total Atomic Mass = 310.3Moles= mass/atomic massMoles = 660/310.3Moles = 2.127M (Concentration) = moles/litresM= 2.127 mol/2.5LM= 0.8508Concentration = 0.8508M
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
The chemical formula is (NH4)HPO4 (if you think to this phosphate). The molar mass is 132,07. The percentages of the elements are: - hydrogen: 6,86997 % - nitrogen: 21,21196 % - oxygen: 48,45843 % - phosphorous: 23,45964 %
The formula mass of calcium acetate (Ca(C2H3O2)2) is calculated by adding the atomic masses of all the atoms in the formula. For calcium acetate, the atomic masses are: Ca (40.08 g/mol) + 2(C) + 3(H) + 2(O). By adding these values, the formula mass for calcium acetate is calculated to be 158.17 g/mol.
The formula mass of magnesium phosphate (Mg3(PO4)2) is calculated by adding the atomic masses of each element in the formula. The atomic mass of magnesium (Mg) is approximately 24.31 g/mol, phosphorus (P) is about 30.97 g/mol, and oxygen (O) is around 16.00 g/mol. Therefore, the formula mass of magnesium phosphate is approximately 262.86 g/mol.