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If empirical formula is C2H5 what is molecular formula?
To find the molecular formula from the empirical formula (C2H5), we need to know the molecular mass of the compound. Since the formula implies a molecular mass of 29 g/mol (12 g/mol for carbon and 1 g/mol for hydrogen), if we divide the molecular mass of the compound by the empirical formula mass (C2H5 = 212 + 51 = 29 g/mol), we find that the molecular formula is the same as the empirical formula, C2H5.
What is the molecular formula of the molecule that has an empirical formula of CH2O and a molar mass of 120.1g?
The empirical formula CH2O has a molar mass of 30.03 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, divide the molar mass given (120.1 g/mol) by the molar mass of the empirical formula to get 4. This means the molecular formula is (CH2O)4, which simplifies to C4H8O4.
What is the molecular formula of a compound if the weight is of a unit of the compound is 120 and the empirical formula is C3H4?
To find the molecular formula, you first need to calculate the empirical formula mass of C3H4. C3H4 has an empirical formula weight of 40 g/mol. If the molecular weight is 120 g/mol, then the molecular formula would be 3 times the empirical formula, so the molecular formula would be C9H12.
What is the molecular weight of silver nitrate?
The formula for silver nitrate is AgNO3. Its molecular weight is 169.87g/mol.
A compound with the empirical formula SN was found in a subsequent experiment to have a molar mass of 184.32 gmol. What is the molecular formula of the compound?
The empirical formula of SN has a formula unit mass of the sum of the gram atomic masses of nitrogen and sulfur, i.e., about 46.0667. The gram molecular mass given in the problem divided by this formula unit mass is about 4. Therefore, the molecular formula is S4N4.
If empirical formula is C2H5 what is molecular formula?
To find the molecular formula from the empirical formula (C2H5), we need to know the molecular mass of the compound. Since the formula implies a molecular mass of 29 g/mol (12 g/mol for carbon and 1 g/mol for hydrogen), if we divide the molecular mass of the compound by the empirical formula mass (C2H5 = 212 + 51 = 29 g/mol), we find that the molecular formula is the same as the empirical formula, C2H5.
Determine the molecular formula for the unknown if the molecular mass is 60.0 amu and the empirical formula is CH2O.?
To determine the molecular formula from the empirical formula CH2O and given molecular mass of 60.0 amu, calculate the empirical formula mass: (12.01 g/mol for C) + 2(1.01 g/mol for H) + 16.00 g/mol for O = 30.02 g/mol. Then divide the given molecular mass by the empirical formula mass to find the factor by which the empirical formula must be multiplied to get the molecular formula: 60.0 amu / 30.02 g/mol ≈ 2. Next, multiply the subscripts in the empirical formula by this factor to find the molecular formula: 2(C)2(H)2(O) = C4H4O2, giving the molecular formula as C4H4O2.
The empirical formula of a compound is CH2O The molar mass of the compound is 180 g What is the molecular formula for this compound?
The empirical formula CH2O has a molar mass of 30 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, which is a multiple of the empirical formula, you divide the molar mass given (180 g/mol) by the empirical formula mass (30 g/mol), giving you 6. Therefore, the molecular formula for the compound is (CH2O)6, which simplifies to C6H12O6, the molecular formula for glucose.
What is the molecular formula of a compound with the empirical formula NH2Cl and molar mass of 51.5g mol?
The empirical formula NH2Cl has a molar mass of 51.5 g/mol, so the molecular formula can be determined by finding the ratio of the molar mass of the molecular formula to the molar mass of the empirical formula. The molecular formula of the compound is therefore NH2Cl2.
What is the molecular formula of the molecule that has an empirical formula of CH2O and a molar mass of 120.1g?
The empirical formula CH2O has a molar mass of 30.03 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, divide the molar mass given (120.1 g/mol) by the molar mass of the empirical formula to get 4. This means the molecular formula is (CH2O)4, which simplifies to C4H8O4.
What is the molecular formula of a compound if the weight is of a unit of the compound is 120 and the empirical formula is C3H4?
To find the molecular formula, you first need to calculate the empirical formula mass of C3H4. C3H4 has an empirical formula weight of 40 g/mol. If the molecular weight is 120 g/mol, then the molecular formula would be 3 times the empirical formula, so the molecular formula would be C9H12.
What is the molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64g?
The molar mass of the compound is 414.64 g/mol. The empirical formula is C13H19O2, which has a molar mass of 13 x 12.01 g/mol + 19 x 1.01 g/mol + 2 x 16.00 g/mol = 203.32 g/mol. To calculate the molecular formula, divide the molar mass of the compound by the molar mass of the empirical formula: 414.64 g/mol / 203.32 g/mol = 2.04. Therefore, the molecular formula is approximately 2 times the empirical formula, which is C26H38O4.
What is the molecular formula of the compound CH2 with molar mass 42.0 gmol?
c3h6
A compound formed of 0.059 mol hydrogen and 0.94 mol oxygen has a molecular mass of 34.0 gmole What is the molecular formula of this compound?
The molar ratio of hydrogen to oxygen in the compound is 2:1. To find the empirical formula, divide the moles of each element by the smallest number of moles, which is 0.059 mol for hydrogen. This gives a ratio of 1:0.5 for hydrogen and oxygen, which simplifies to the empirical formula H2O. To find the molecular formula, calculate the molecular mass of H2O (18 g/mol) and divide the given molecular mass (34 g/mol) by the empirical formula mass to get the multiplier of 2. So, the molecular formula of the compound is H2O2.
What is the molecular formula of compound CH2 with a molar mass of 42.0?
The molecular formula of compound CH2 with a molar mass of 42.0 g/mol is C2H4, which is ethylene. Each carbon has a molar mass of 12.0 g/mol, and each hydrogen has a molar mass of 1.0 g/mol, totaling 42.0 g/mol.
Styrene has the empirical formula CH. It has a molar mass of 104 g. What is the multiplier to get the molecular formula?
The molar mass of styrene (C8H8) is 104 g/mol. The empirical formula is CH, which has a molar mass of 13 g/mol. To find the multiplier to get the molecular formula from the empirical formula, divide the molar mass of the molecular formula by the molar mass of the empirical formula: 104 g/mol / 13 g/mol = 8. This means the multiplier is 8, and the molecular formula of styrene is C8H8.
What is the molecular formula of a substance that has an empirical formula of C2H5 and a molecular mass of 58 grams per mole?
The empirical formula of C2H5 corresponds to an empirical mass of 29 g/mol. To find the molecular formula from the empirical formula and molecular mass, divide the molecular mass by the empirical mass to get the "scaling factor" (58 g/mol ÷ 29 g/mol = 2). Multiply the subscripts in the empirical formula by the scaling factor to get the molecular formula: C2H5 x 2 = C4H10. So, the molecular formula is C4H10.
