4 Osm
I assume you mean 0.5 molar, but I'll go with what I'm given. If you have 500 molar of barium chloride, you will have 1000 molar of chloride ions as there are 2 chlorides for every 1 molecule of barium chloride. Having the 100ml there is irrelevant as you are talking about concentration and didn't ask for moles.
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
2(IIA) Because The elements in Group 2 (IIA) are metals with a +2 oxidation state. Thus one atom of a Group 2 metal can combine with 2 atoms of chlorine (oxidation state = -1)
To find the number of moles in 80 grams of calcium, you would first calculate the molar mass of calcium (40.08 g/mol), then divide the given mass by the molar mass to get the number of moles. In this case, 80 grams of calcium would be 2 moles.
The answer is 18 inner electrons for Calcium (atom number 20)The first three shells of Ca are 'inner', the last, 4th, contains the 2 valence electronsSo (K,L,M,N) = 2, 8, 8, 2
Calcium chloride is a compound. Assuming the 50 m actually means 50 mol, this number at the beginning is a distractor and does not impact the problem.
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
The freezing point of a 2.65 m calcium chloride (CaCl2) solution is approximately -5.4°C. This can be calculated using the Van't Hoff factor for CaCl2 as 3 (since it dissociates into 3 ions), in combination with the formula for freezing point depression.
To calculate the osmolarity of 85 M K₃PO₄, we need to consider the dissociation of the compound in solution. K₃PO₄ dissociates into 3 potassium ions (K⁺) and 1 phosphate ion (PO₄³⁻), resulting in a total of 4 particles per formula unit. Therefore, the osmolarity is calculated as 85 M × 4 = 340 Osm/L.
Element M is calcium. It reacts with chlorine to form calcium chloride (CaCl2). Calcium is more reactive than magnesium and smaller than barium on the periodic table.
-14.8 Celsius
You'll need: 0.450 (L) * 25 (mol/L) = 11.25 mol CaCl2 and add water to it up to 450 mL.To be weighted:11.25 (mol CaCl2) * [40.08 + 2*35.45](g/mol CaCl2) = 1491.736 g = 1500 g =1.5 kg CaCl2 (CaCl2 as dry substance!, not hydrated)
Milk contains calcium.
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
I assume you mean 0.5 molar, but I'll go with what I'm given. If you have 500 molar of barium chloride, you will have 1000 molar of chloride ions as there are 2 chlorides for every 1 molecule of barium chloride. Having the 100ml there is irrelevant as you are talking about concentration and didn't ask for moles.