0
What else can I help you with?
What is the molarity of chloride ion in 100 ml of a 500 M barium chloride solution?
I assume you mean 0.5 molar, but I'll go with what I'm given. If you have 500 molar of barium chloride, you will have 1000 molar of chloride ions as there are 2 chlorides for every 1 molecule of barium chloride. Having the 100ml there is irrelevant as you are talking about concentration and didn't ask for moles.
How many grams of silver nitrate can be produced by the reaction of 100.0 ml of 0.20 M silver nitrate and 100.0 ml of 0.15 M calcium chloride?
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
Element M is a metal and its chloride has the formula MCl2 To which group of the Periodic Table does element M most likely belong?
2(IIA) Because The elements in Group 2 (IIA) are metals with a +2 oxidation state. Thus one atom of a Group 2 metal can combine with 2 atoms of chlorine (oxidation state = -1)
How many moles of calcium is in 80 grams?
To find the number of moles in 80 grams of calcium, you would first calculate the molar mass of calcium (40.08 g/mol), then divide the given mass by the molar mass to get the number of moles. In this case, 80 grams of calcium would be 2 moles.
What is the normal number of inner electrons in calcium?
The answer is 18 inner electrons for Calcium (atom number 20)The first three shells of Ca are 'inner', the last, 4th, contains the 2 valence electronsSo (K,L,M,N) = 2, 8, 8, 2
If there is 0.2 M glucose along with 0.15 M NaCl in solution what is the osmolarity of this solution?
To calculate the osmolarity of the solution, we consider the dissociation of solutes. Glucose does not dissociate, contributing 0.2 osmoles per liter. Sodium chloride (NaCl) dissociates into two ions (Na⁺ and Cl⁻), contributing 0.15 M × 2 = 0.30 osmoles per liter. Therefore, the total osmolarity is 0.2 + 0.30 = 0.50 osmoles per liter.
Is 50 m calcium chloride a compound?
Calcium chloride is a compound. Assuming the 50 m actually means 50 mol, this number at the beginning is a distractor and does not impact the problem.
How many grams of calcium chloride are needed to make a 0.01 M solution?
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
How many grams of calcium chloride will you add to 250mL of water to make a 0.236 M solution?
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
What is the freezing point of an aqueous 2.65 m calcium chloride CaCl2 solution?
The freezing point of a 2.65 m calcium chloride (CaCl2) solution is approximately -5.4°C. This can be calculated using the Van't Hoff factor for CaCl2 as 3 (since it dissociates into 3 ions), in combination with the formula for freezing point depression.
How do you prepare 0.05M calcium chloride?
To prepare a 0.05 M calcium chloride (CaCl₂) solution, first calculate the required mass of CaCl₂ by using its molar mass, which is approximately 110.98 g/mol. For 1 liter of a 0.05 M solution, dissolve 5.55 grams of anhydrous CaCl₂ in distilled water. Add the calcium chloride to a volumetric flask, then fill the flask with distilled water up to the 1-liter mark. Mix thoroughly to ensure the solute is fully dissolved.
What is the osmolarity of 85 M of K3PO4?
To calculate the osmolarity of 85 M K₃PO₄, we need to consider the dissociation of the compound in solution. K₃PO₄ dissociates into 3 potassium ions (K⁺) and 1 phosphate ion (PO₄³⁻), resulting in a total of 4 particles per formula unit. Therefore, the osmolarity is calculated as 85 M × 4 = 340 Osm/L.
Element M reacts with chlorine to form a compound with the formula MCl2 It is more reactive than magnesium and smaller than barium This element is?
Element M is calcium. It reacts with chlorine to form calcium chloride (CaCl2). Calcium is more reactive than magnesium and smaller than barium on the periodic table.
What is the freezing point of an aqueous 265 m calcium chloride CaCI2 solution the freezing point of pure water is 00 degrees Celsius and kf of pure water is -186 degrees Celsius over m?
-14.8 Celsius
What mass of calcium chloride is needed to prepare 2.85 L of a 1.56 M solution?
To calculate the mass of calcium chloride (CaCl₂) required for a 1.56 M solution, first use the formula: [ \text{mass (g)} = \text{molarity (mol/L)} \times \text{volume (L)} \times \text{molar mass (g/mol)} ] The molar mass of CaCl₂ is approximately 110.98 g/mol. Therefore, for 2.85 L of a 1.56 M solution: [ \text{mass} = 1.56 , \text{mol/L} \times 2.85 , \text{L} \times 110.98 , \text{g/mol} \approx 49.3 , \text{g} ] Thus, about 49.3 grams of calcium chloride is needed.
How would you make 450 mL of a 25 M calcium chloride solution?
You'll need: 0.450 (L) * 25 (mol/L) = 11.25 mol CaCl2 and add water to it up to 450 mL.To be weighted:11.25 (mol CaCl2) * [40.08 + 2*35.45](g/mol CaCl2) = 1491.736 g = 1500 g =1.5 kg CaCl2 (CaCl2 as dry substance!, not hydrated)
How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
