n=m/M
n= 80 g/40.078 g/mol
n=1.996mol
Probably about 80%. This is what I have heard and learnt.
Sulfuric acid has a molecualr weight of 98 and so 2.5 moles would weigh 245 g
The key is to understand that Mg is limiting. Therefore, the final number of moles of H2 will equal the starting number of moles of Mg. Using gas law equations we can first find the moles of H2 and then find the moles of Mg. 1. PV = nRT --> n = PV/RT P = 760 mm Hg (pressure at STP) V = 80.0 mL (given) R = 62,400 mL-mm Hg/mol-K (constant) T = 273 K (temp. at STP) Now you have all the information you need to solve for the number of moles of Mg. Solve for moles and convert to grams.
when 60 grams of ice melts , there will be 60 grams of liquid water left.
The relationship between number of moles and mass is: n = m/MW Where n is the number of moles, m is the mass in grams and MW is the molecular weight (or molecular mass). Subsituting the numbers into the equation: 2.5 mol = m/32 (from O2(g), 16 from each oxygen) m = 2.5 * 32 = 80 grams This also means that there is approximately 1.5 x 1024 molecules of O2 in your sample.
molar mass SO3 = 80 g/mole. 1.12 moles x 80 g/mole = 89.6 grams
Need an equation as this is not familiar to me. Where is the carbon coming from? Moles? Molarity. All info I do not have.
2 moles 80/40= 2
80 milligrams8 centigrams0.8 decigrams0.08 grams
Molarity = moles of solute/volume of solution 0.53 M NaOH = moles NaOH/3.8 Liters = 2.014 moles, or about 80 grams
80 grams is 1/3 cup
80 g = about 0.1764 pounds.
The molecular mass of iron(III) chloride is 55.8 + 3(35.5) = 162.3 Amount of iron (III) chloride in a 80.5g pure sample = 80.5/162.3 = 0.496mol
0.08 grams
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
Probably about 80%. This is what I have heard and learnt.
2,268 Grams