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Iodine dissolves readily in CCl4 due to the presence of London dispersion forces between the iodine molecules and the non-polar CCl4 molecules. These weak intermolecular forces allow for iodine molecules to be dispersed throughout the CCl4 solvent.
When iodine is dissolved in tetrachloromethane, it forms a purple solution due to the interaction between iodine molecules and the tetrachloromethane solvent, resulting in a complex known as iodine in tetrachloromethane. This solution is commonly used in chemistry as a reagent for testing double bonds in organic compounds.
No, KCl (potassium chloride) and CCl4 (carbon tetrachloride) cannot form a solution because they have very different chemical properties. KCl is an ionic compound that dissociates into potassium and chloride ions in water, while CCl4 is a nonpolar covalent compound that is not soluble in water.
The balanced chemical equation for this reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. From the equation, it can be seen that 1 mole of CH4 produces 1 mole of CCl4. Therefore, 8.00 g of CH4 would produce 8.00 g of CCl4.
yes it will because both iodine I2 and Carbon tetrachloride CCL4 are both non polar It will turn a deep violet color when reacted Remeber the phrase, " like dissolves like" this is different interms of water. Although Iodine is to some degree soluble in water, it is not as soluble as it is in CCL4, because water is a poler compound, remember positive and negative deltas's so in this case it is polar water cannot effiviently dissolve nonpolar Iodine
Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
Iodine dissolves readily in CCl4 due to the presence of London dispersion forces between the iodine molecules and the non-polar CCl4 molecules. These weak intermolecular forces allow for iodine molecules to be dispersed throughout the CCl4 solvent.
When iodine is dissolved in tetrachloromethane, it forms a purple solution due to the interaction between iodine molecules and the tetrachloromethane solvent, resulting in a complex known as iodine in tetrachloromethane. This solution is commonly used in chemistry as a reagent for testing double bonds in organic compounds.
The reaction CCl4 + 2Cl2 → C + 2CCl2 is a redox reaction, specifically a displacement reaction where CCl4 is being reduced to C and Cl2 is being oxidized to CCl2.
Inert solvent is a solvent that does not react with your reaction system. means, it does not interfere between your reactants . . .Inert solvent like CCL4 does not do anything to Bromine, e.g. Bromine water, which is red-brown in colour, when added to CCL4 , its colour remains same.
Any reaction occur.
No, KCl (potassium chloride) and CCl4 (carbon tetrachloride) cannot form a solution because they have very different chemical properties. KCl is an ionic compound that dissociates into potassium and chloride ions in water, while CCl4 is a nonpolar covalent compound that is not soluble in water.
In the presence of aqueous NaOH, phenol undergoes nucleophilic aromatic substitution reaction to form sodium phenoxide. When CCl4 is added, no reaction occurs as CCl4 is non-reactive towards phenoxide ion.
The balanced equation for the reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. 1 mole of CH4 produces 1 mole of CCl4. Calculate moles of CH4: 5.14 g / 16.04 g/mol = 0.32 mol. 0.32 mol of CH4 will produce 0.32 mol of CCl4, which is 0.32 * 153.82 g/mol = 49.18 g of CCl4.
The balanced chemical equation for this reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. From the equation, it can be seen that 1 mole of CH4 produces 1 mole of CCl4. Therefore, 8.00 g of CH4 would produce 8.00 g of CCl4.
This chemical reaction is:CS2 + 3 Cl2 = CCl4 + S2Cl2
The reaction you listed does not balance. However, if you meant CCl4 (carbon tetrachloride) instead of CCl2, the balanced equation would be CCl4 + Cl2 -> CCl3Cl + HCl. The reaction involves chlorine transforming carbon tetrachloride into chloroform and hydrogen chloride.