Well... It seems to be C43H88 which is TRITETRACONTANE.
Hope this helped!
To find the molecular formula, you first need to calculate the empirical formula mass of C3H4. C3H4 has an empirical formula weight of 40 g/mol. If the molecular weight is 120 g/mol, then the molecular formula would be 3 times the empirical formula, so the molecular formula would be C9H12.
C4H8 can refer to either an alkene or an alkane. In the case of an alkene, it would be 1-butene, while for an alkane, it would be 2-methylpropene. The distinction can be made based on the presence of a double bond in the alkene.
The molecular formula of a compound is a multiple of its empirical formula, so the molecular formula is a multiple (in this case, 6 times) of CH2O, giving C6H12O6. This molecular formula corresponds to glucose, a common sugar.
To find the molecular formula from the empirical formula (C2H5), we need to know the molecular mass of the compound. Since the formula implies a molecular mass of 29 g/mol (12 g/mol for carbon and 1 g/mol for hydrogen), if we divide the molecular mass of the compound by the empirical formula mass (C2H5 = 212 + 51 = 29 g/mol), we find that the molecular formula is the same as the empirical formula, C2H5.
Molecular nitrogen is: N2 Molecular bromide is: Br2 Nitrogen tribromide is: NBr3
An alkane with 20 carbons will have 42 hydrogens. This can be calculated using the formula 2n+2, where n is the number of carbons (C) in the alkane. So for an alkane with 20 carbons, the number of hydrogens would be 2(20) + 2 = 42.
The alkane with 100 hydrogen would be C49H100.The 100 hydrogen will have 49 carbons attached.The carbons on the ends would have 3 hydrogen each so the hydrogen left are 94 so the Carbon in the chain can only have 2 hydrogen each.Therefore the no of hydrogen in between will have 47 carbons and two carbons on the end. 47+2 =49 carbons.
For a straight-chain alkane, this would be C10H22 - decane. However, if this is a cyclic alkane, you would have C10H20 (cyclodecane). There are also numerous options for a branching alkane with various names and carbon to hydrogen ratios.
Assuming the hydrocarbon is saturated the formula would be C21H44 In a saturated hydrocarbon the number of hydrogen atoms is equal to twice the number of carbon atoms, plus two.
Yes, a compound with the chemical formula C15H30 would be a member of the alkane series. Alkanes have the general formula CnH2n+2, where n represents the number of carbon atoms in the alkane molecule. In this case, n=7, so the compound falls into the alkane series.
Alkanes have the general formula of CnH2n+2 so for 12 carbons, that would be 2x12 + 2 = 26 hydrogen atoms.
The empirical formula C2H3 has a molecular mass of 27 (C: 12, H: 1). To determine the molecular formula with a molecular mass of 54, the molecular formula would simply be double the empirical formula, so the molecular formula would be C4H6.
In an alkane the number of hydrogen atoms is two greater than twice the number of carbon atoms. If we reverse this rule, we find that the number of carbon atoms is one less than half the number of hydrogen atoms. 32/2=16 16-1=15 So our alkane would have 15 carbon atoms. This alkane would be pentadecane or one of its isomers.
To find the molecular formula, you first need to calculate the empirical formula mass of C3H4. C3H4 has an empirical formula weight of 40 g/mol. If the molecular weight is 120 g/mol, then the molecular formula would be 3 times the empirical formula, so the molecular formula would be C9H12.
Ammonia and nitrogen are two distinct compounds, not a single compound that would have a molecular formula.
C4H8 can refer to either an alkene or an alkane. In the case of an alkene, it would be 1-butene, while for an alkane, it would be 2-methylpropene. The distinction can be made based on the presence of a double bond in the alkene.
The generic formula for an alkane is CnH(2n + 2).Therefore, an alkane with 3 carbon atoms would have 8 hydrogen atoms.