Well... It seems to be C43H88 which is TRITETRACONTANE.
Hope this helped!
The simplest possibility is the same as the empirical formula, which is the molecular formula of formaldehyde, although it would probably more often be written as H2CO.
The molecular formula would have to be C4H10 as the number of hydrogen atoms cannot exceed 2+2X where X is the number of carbon atoms.
Yes. It is called hexane because of the six carbon atoms per molecule.
Yes but you have to draw it as a 3 carbon ring structure (like a triangle) and the 1st carbon would have a CH3 and an OH.
Yes, if you have some additional information, such as the molecular weight. For instance, the molecules C2H4 and C4H8 have exactly the same percent composition, but they are very different molecules. So you need some other information to tell them apart than the percent composition.Answer ExpandedThis is kind of a trick question. By knowing the percent composition, you would easily be able to determine its empirical formula, but molecular formula is a bit different. The molecular formula is the actual number of atoms in a molecule, so in order to find the specific molecular formula of a substance, you would also need to know how many grams there is of that substance.(This explains the difference between C2H4 and C4H8)
The alkane with 100 hydrogen would be C49H100.The 100 hydrogen will have 49 carbons attached.The carbons on the ends would have 3 hydrogen each so the hydrogen left are 94 so the Carbon in the chain can only have 2 hydrogen each.Therefore the no of hydrogen in between will have 47 carbons and two carbons on the end. 47+2 =49 carbons.
For a straight-chain alkane, this would be C10H22 - decane. However, if this is a cyclic alkane, you would have C10H20 (cyclodecane). There are also numerous options for a branching alkane with various names and carbon to hydrogen ratios.
Assuming the hydrocarbon is saturated the formula would be C21H44 In a saturated hydrocarbon the number of hydrogen atoms is equal to twice the number of carbon atoms, plus two.
It would be a molecular formula for C3h5o.
Alkanes have the general formula of CnH2n+2 so for 12 carbons, that would be 2x12 + 2 = 26 hydrogen atoms.
Yes, it is possible for an empirical formula to be the same as the molecular formula. For example, Lactic acid's molecular formula is C3H6O3, which would make its empirical formula CH2O.
C24H50 is an alkane molecule, like all CnH2n+2 molecular formulated compounds are; they can be linear or branched all single bonded C atoms of the following groups or types: (Each line ' - ' or ' | ' is a covalent bond to another C atom; Ignore the dots .. , they're only for layout) -CH3 -CH2- -CH- .. | . | -C- . |
In an alkane the number of hydrogen atoms is two greater than twice the number of carbon atoms. If we reverse this rule, we find that the number of carbon atoms is one less than half the number of hydrogen atoms. 32/2=16 16-1=15 So our alkane would have 15 carbon atoms. This alkane would be pentadecane or one of its isomers.
Yes, ethane is the only 2-carbon alkane.
Ammonia and nitrogen are two distinct compounds, not a single compound that would have a molecular formula.
A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.
A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.