One electron from each sodium atom is transferred to the outermost shell of a bromine atom, thereby forming a sodium cation and a bromide anion. If the transfer takes place at a temperature below the melting point of the salt sodium bromide, a solid product results, as the ions spontaneously migrate into their lowest energy positions in a crystal lattice of sodium bromide.
Bromine is an element and can't be "made" from any other element (except by a nuclear reaction). However, since the question asks for a sodium compound, one possibility is sodium bromide, which can be melted and electrolyzed to form bromine at the anode.
Sodium electronegativity (after Pauling): 0,93 Bromine electronegativity (after Pauling): 2,96 The difference is 2,03.
the difference between the electronegativity values of sodium and bromine is 1.9 , which is relatively high in general , high differences suggest ionic bonds.
We know that the alkali metal sodium (Na) will form an ionic bond with the halogen bromine (Br) to create sodium bromide (NaBr). The equation looks like this: Na + Br => NaBr
The compound formed between sodium and selenium is named "sodium selenide" and has the formula Na2Se.
The compound sodium bromide is formed by the formation of ionic bonds between sodium and bromide ions.
Sodium Bromide - ionic compound - NaBr.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
Bromine is an element and can't be "made" from any other element (except by a nuclear reaction). However, since the question asks for a sodium compound, one possibility is sodium bromide, which can be melted and electrolyzed to form bromine at the anode.
An extremely exothermic reaction occurs producing Sodium Bromide
The chemical compound of sodium and bromine is sodium bromide -NaBr.NaBr is used as drug (sedative agent), disinfectant, preparation of dense fluids for oil extraction.
Sodium and bromine are chemical elements, not properties; the chemical reaction between sodium and bromine is a chemical process, not a property.
Yes it is anionic compound because, We know that the alkali metal sodium (Na) will form an ionic bond with the halogen bromine (Br) to create sodium bromide (NaBr). The equation looks like this:Na + Br => NaBr
Sodium electronegativity (after Pauling): 0,93 Bromine electronegativity (after Pauling): 2,96 The difference is 2,03.
Sodium electronegativity (after Pauling): 0,93 Bromine electronegativity (after Pauling): 2,96 The difference is 2,03.
Generally a metal with a nonmetal forms an ionic bond. Sodium is a metal and bromine is a nonmetal, so they will form an ionic bond, forming the compound sodium bromide, NaBr.
Sodium selenide is a compound formed between sodium and selenium.