Noble Gas
Noble gas, such as neon. Sodium loses an electron to achieve a stable electron configuration like neon (2, 8) in the outer shell, while chlorine gains one electron to attain an electron configuration like argon (2, 8, 8).
In sodium chloride, sodium (Na) loses an electron to chlorine (Cl). Sodium donates an electron to chlorine in order to achieve a stable electron configuration, forming a sodium cation (Na+) and a chloride anion (Cl-).
The atomic number of Sodium is 11 (2,8,1), so there is one electron in the outer-most shell. As soon as sodium looses this outer-most one electron, it acquires the stable most structure with a 2,8. That';s why sodium ion is stabler than sodium metal. The electronic configuration of a sodium ion is 2,8. Same thing happens with Chlorine. The electronic configuration of chlorine is 2,8,7. Chlorine needs just one electron to stabilize itself with a configuration of 2,8,8. When the chlorine atom gains one electron, it forms the chlorine ion which has the configuration 2,8,8 which is stable.
Chlorine will have a noble gas configuration by accepting one electron from a sodium atom to form an ionic bond. This results in chlorine gaining a full outer electron shell, similar to the noble gas configuration of argon.
accepts an electron to become the chloride anion, Cl-
Noble gas, such as neon. Sodium loses an electron to achieve a stable electron configuration like neon (2, 8) in the outer shell, while chlorine gains one electron to attain an electron configuration like argon (2, 8, 8).
When sodium (Na) bonds with chlorine (Cl), sodium donates one electron to chlorine. As a result, chlorine achieves a stable electron configuration resembling that of the nearest noble gas, argon. Chlorine ends up with a full outer shell containing eight electrons, giving it the electron configuration of (1s^2 2s^2 2p^6), which is characteristic of a stable, anionic form (Cl⁻).
in sodium chloride chlorine gains an electron and the bond formed between then is ionic.
Sodium reacts with chlorine gas because sodium wants to donate its electron to chlorine to achieve a stable electron configuration, and chlorine wants to gain an electron to also become stable. This electron transfer results in the formation of ionic bonds between sodium and chlorine atoms, leading to the creation of sodium chloride (table salt).
One electron is transferred from sodium to chlorine in the ionic bond between sodium and chlorine in NaCl. Sodium loses one electron to achieve a stable electron configuration with a full outer shell, becoming a positively charged ion (Na+), while chlorine gains this electron to achieve a stable electron configuration, becoming a negatively charged ion (Cl-).
Sodium has one outer ring electron, and chlorine has seven outer ring electrons. Sodium tends to lose its outer electron, while chlorine tends to gain an extra electron to achieve a stable electron configuration.
Sodium has 1 electron in its outer shell, while chlorine has 7 electrons in its outer shell. To achieve a stable electron configuration, sodium will donate its electron to chlorine, forming an ionic bond. This results in sodium losing 1 electron and chlorine gaining 1 electron to form sodium chloride.
Sodium is an element which has one electron in its outer electron shell, and which can obtain a more stable electron configuration by getting rid of that electron. This causes it to undergo chemical reactions with other elements such as oxygen or chlorine, which need to acquire electrons in order to obtain a more stable electron configuration. If sodium reacts with water, it is reacting with the oxygen in the water molecule. In the case of sodium chloride, the sodium has already reacted with chlorine to form that compound, and has given up its outer electron, so it no longer needs to react with oxygen in water.
Sodium would most likely form an ionic bond with chlorine to form sodium chloride (table salt). Sodium easily loses an electron to achieve a stable electron configuration, while chlorine easily gains an electron to achieve a stable electron configuration.
In sodium chloride, sodium (Na) loses an electron to chlorine (Cl). Sodium donates an electron to chlorine in order to achieve a stable electron configuration, forming a sodium cation (Na+) and a chloride anion (Cl-).
The atomic number of Sodium is 11 (2,8,1), so there is one electron in the outer-most shell. As soon as sodium looses this outer-most one electron, it acquires the stable most structure with a 2,8. That';s why sodium ion is stabler than sodium metal. The electronic configuration of a sodium ion is 2,8. Same thing happens with Chlorine. The electronic configuration of chlorine is 2,8,7. Chlorine needs just one electron to stabilize itself with a configuration of 2,8,8. When the chlorine atom gains one electron, it forms the chlorine ion which has the configuration 2,8,8 which is stable.
Chlorine will have a noble gas configuration by accepting one electron from a sodium atom to form an ionic bond. This results in chlorine gaining a full outer electron shell, similar to the noble gas configuration of argon.