Al(OH)3 + 3NaNO3 >> Al(NO3)3 + 3NaOH
This is a double displacement reaction between metals ( Aluminum is a transition metal, but has only a 3+ oxidation state. ) and polyatomic ions of negative charge. Both are 1- in charge. Sodium is 1+ in charge. This is why the atoms are arranged as they are with the polyatomic ions enclosed in parentheses where needed. Remember, botgh sides of the equation musr contain the same number of atoms. Count carefully and you will see this is the case.
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
The balanced equation for the reaction of aluminum and iodine to form aluminum iodide is: 2Al + 3I2 -> 2AlI3
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
The balanced equation for the reaction between aluminum hydroxide and permanganic acid is: 2Al(OH)3 + 5H2MnO4 -> 2Al(MnO4)3 + 6H2O + 5MnO2
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
The balanced equation for the reaction of aluminum and iodine to form aluminum iodide is: 2Al + 3I2 -> 2AlI3
The word equation for aluminum sulfate is: aluminum sulfate + water → aluminum hydroxide + sulfuric acid.
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
(*Warning!!Xb42 is a atomic chemical,so do not mix aluminum oxide and dilute potassium hydroxide!!*)
The balanced neutralization reaction between phosphorus acid (H3PO3) and aluminum hydroxide (Al(OH)3) produces aluminum phosphate (AlPO4) and water (H2O). The balanced chemical equation is: 2H3PO3 + 3Al(OH)3 → 2AlPO4 + 6H2O
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
The balanced equation for the decomposition of aluminum oxide is: 2Al2O3(s) → 4Al(s) + 3O2(g)