Al(OH)3 + 3NaNO3 >> Al(NO3)3 + 3NaOH
This is a double displacement reaction between metals ( Aluminum is a transition metal, but has only a 3+ oxidation state. ) and polyatomic ions of negative charge. Both are 1- in charge. Sodium is 1+ in charge. This is why the atoms are arranged as they are with the polyatomic ions enclosed in parentheses where needed. Remember, botgh sides of the equation musr contain the same number of atoms. Count carefully and you will see this is the case.
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
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what are the products of the reaction between aluminum chloride and cesium
A balanced equation MUST have EQUAL numbers of EACH type of atom on BOTH sides of the arrow.The correctly balanced equation is:The equation for sodium hydroxide and aluminum sulfate is written as follows.Al2(SO4)3(s) + 6 NaOH(aq) 2 Al(OH)3(s) + 6 Na+(aq) + 3 SO42–(aq)
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
When aluminum carbide reacts with water, the products of the reaction are aluminum hydroxide and methane gas. The balanced equation for this reaction is Al4C3 + 12H2O -->4Al(OH)3 + 3CH4(g)
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Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
what are the products of the reaction between aluminum chloride and cesium
The reaction is not possible.
A balanced equation MUST have EQUAL numbers of EACH type of atom on BOTH sides of the arrow.The correctly balanced equation is:The equation for sodium hydroxide and aluminum sulfate is written as follows.Al2(SO4)3(s) + 6 NaOH(aq) 2 Al(OH)3(s) + 6 Na+(aq) + 3 SO42–(aq)
Aluminum hydroxide plus hydrochloric acid equals( produces ) aluminum chloride plus water.
2Al(OH)3 ==> Al2O3 + 3HOH =)
2Al + 3Cl2 -> 2AlCl3
Al(OH)3(s) + 3 H+(aq) --> Al3+(aq) + 3 H2O(I)
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).